Chapter 14, Problem 14.62P

Reaction of ${\left({\text{CH}}_{\text{3}}\right)}_{\text{3}}\text{CCHO}$ with ${\left({\text{C}}_{\text{6}}{\text{H}}_{\text{5}}\right)}_{\text{3}}\text{P}=\text{C}\left({\text{CH}}_{\text{3}}\right){\text{OCH}}_{\text{3}}$, followed by treatment with aqueous acid, affords R $\left({\text{C}}_{\text{7}}{\text{H}}_{\text{14}}\text{O}\right)$. R has a strong absorption in its IR spectrum at $1717{\text{cm}}^{-1}$ and three singlets in its ${}^1\text{H}\text{NMR}$ spectrumat $\text{1}\text{.02}\left(9\text{H}\right)\text{,}\text{2}\text{.13}\left(\text{3}\text{H}\right)$, and $\text{2}\text{.33}\left(\text{2}\text{H}\right)\text{ppm}$. What is the structure of R? We will learn about this reaction in Chapter 21.