Interpretation: The use of water as a cooling agent in nature and in industry has to be described.
Concept introduction:The most common coolant is water. The heat capacity of water is high and is cost efficient, which makes water a suitable medium for heat-transfer. Water can be used with corrosion inhibitors, additives and antifreeze.
Answer to Problem 11A
In nature, water is used in the process of perspiration on a hot day.
In industry, water is used to cool generators, steam electric power plants, cooling of lubricant oil in pumps, etc.
Explanation of Solution
A substance could act as an effective coolant, when it has a high specific heat capacity that is a large amount of heat could be absorbed.
The most common coolant is water. The heat capacity of water is high and iscost efficient, which makes water a suitable medium for heat-transfer. Water can be used with corrosion inhibitors, additives and antifreeze.
Some of the industrial applications of water are:
- Deionized water is used to cool some electrical equipment’s such as high-power transmitters and high-power vacuum tubes due to its low electrical conductivity.
- Heavy water is used as neutron moderator in nuclear reactors.
- In power plants, water is used to cool generators.
- Water is used as cooling agent in steam electric power plants.
- Water is used for cooling automobile internal combustion engines.
- Water as a coolant could also be used in petroleum refineries, chemical plants and for cooling purposes in heat exchangers.
In nature, water is usedas a coolant in the process of perspiration. Perspiration is otherwise known as a sweating. In humans, sweating is achieved by water-rich secretion of the sweat glands. Evaporation of sweat from the surface of skin has a cooling effect due to evaporative cooling.
In nature, water is used in the process of perspiration on a hot day.
In industry, water is used to cool generators, steam electric power plants, cooling of lubricant oil in pumps, etc.
Chapter 14 Solutions
World of Chemistry, 3rd edition
- Rank the following compounds most to least acidic: a) О OH 요애 OH .OH flow flow О F F F F OH F b) Ha EN-Ha CI Ha F F CI Haarrow_forwarda) b) Provide arrows to show the mechanisms and then predict the products of the following acid base reaction. Use pKas to determine which way the reaction will favor (Hint: the lower pka acid will want to dissociate) Дон OH Ha OH NH2 c) H H-O-Harrow_forwardMATERIALS. Differentiate between interstitial position and reticular position.arrow_forward
- For each of the following, indicate whether the arrow pushes are valid. Do we break any rules via the arrows? If not, indicate what is incorrect. Hint: Draw the product of the arrow and see if you still have a valid structure. a. b. N OH C. H N + H d. e. f. مه N COHarrow_forwardDecide which is the most acidic proton (H) in the following compounds. Which one can be removed most easily? a) Ha Нь b) Ha Нь c) CI CI Cl Ha Ньarrow_forwardProvide all of the possible resonanse structures for the following compounds. Indicate which is the major contributor when applicable. Show your arrow pushing. a) H+ O: b) c) : N :O : : 0 d) e) Оarrow_forward
- Draw e arrows between the following resonance structures: a) b) : 0: :0: c) :0: N t : 0: بار Narrow_forwardDraw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl Substitution will not occur at a significant rate. Explanation Check :☐ O-CH + Х Click and drag to start drawing a structure.arrow_forwardDraw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. Cl C O Substitution will not occur at a significant rate. Explanation Check + O-CH3 Х Click and drag to start drawing a structure.arrow_forward
- ✓ aw the major substitution products you would expect for the reaction shown below. If substitution would not occur at a significant rate under these conditions, check the box underneath the drawing area instead. Be sure you use wedge and dash bonds where necessary, for example to distinguish between major products. Note for advanced students: you can assume that the reaction mixture is heated mildly, somewhat above room temperature, but strong heat or reflux is not used. C Cl HO–CH O Substitution will not occur at a significant rate. Explanation Check -3 ☐ : + D Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Cearrow_forwardPlease correct answer and don't used hand raitingarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
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