Chapter 13.7, Problem 14PSB

To determine

To find:The area of $\Delta ABC$ .

Answer to Problem 14PSB

The area of $\Delta ABC$ is $18\text{sq}\text{.unit}$ .

Explanation of Solution

The area of $\Delta ABC$ is calculated as,

  $\begin{array}{c}A\left(\Delta ABC\right)=\left(5\times 8\right)-\frac{2\times 5}{2}-\frac{2\times 8}{2}-\frac{3\times 6}{2}\\ =40-5-8-9\\ =18\text{sq}\text{.unit}\end{array}$

Therefore, the area of $\Delta ABC$ is $18\text{sq}\text{.unit}$ .