Geometry For Enjoyment And Challenge
Geometry For Enjoyment And Challenge
91st Edition
ISBN: 9780866099653
Author: Richard Rhoad, George Milauskas, Robert Whipple
Publisher: McDougal Littell
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Chapter 13.2, Problem 20PSC

(a)

To determine

To find: The number of pairs of numbers in the given figure.

(a)

Expert Solution
Check Mark

Answer to Problem 20PSC

The number of pairs of numbers in the given figure are 16.

Explanation of Solution

Given:

The given figure is as follows.

  Geometry For Enjoyment And Challenge, Chapter 13.2, Problem 20PSC , additional homework tip  1

Calculation:

As shown in the given figure there are total 16 dots, so there are total 16 pairs of numbers.

(b)

To determine

To find: The probability that x=y .

(b)

Expert Solution
Check Mark

Answer to Problem 20PSC

The probability that x=y is 14 .

Explanation of Solution

Given:

The given figure is as follows.

  Geometry For Enjoyment And Challenge, Chapter 13.2, Problem 20PSC , additional homework tip  2

Calculation:

There are total 16 dots.

There are four possible cases (0,0) , (1,1) , (2,2) , and (3,3) which have y=x .

Find the probability that x=y is as follows.

  p=416=14

Therefore, the probability that x=y is 14 .

(c)

To determine

To show: The points on the graph for which x<y .

(c)

Expert Solution
Check Mark

Answer to Problem 20PSC

The points on the graph for which x<y are shown in figure (1).

Explanation of Solution

Given:

The given figure is as follows.

  Geometry For Enjoyment And Challenge, Chapter 13.2, Problem 20PSC , additional homework tip  3

Calculation:

The points on the graph for which x<y are shown below.

  Geometry For Enjoyment And Challenge, Chapter 13.2, Problem 20PSC , additional homework tip  4

Figure (1)

(d)

To determine

To find: The probability that x<y .

(d)

Expert Solution
Check Mark

Answer to Problem 20PSC

The probability that x<y is 616 .

Explanation of Solution

Given:

The given figure is as follows.

  Geometry For Enjoyment And Challenge, Chapter 13.2, Problem 20PSC , additional homework tip  5

Calculation:

There are 6 dots out of 16 which has x<y .

The probability that x<y is as follows.

  p=616

Therefore, the probability that x<y is 616 .

Chapter 13 Solutions

Geometry For Enjoyment And Challenge

Ch. 13.1 - Prob. 11PSACh. 13.1 - Prob. 12PSBCh. 13.1 - Prob. 13PSBCh. 13.1 - Prob. 14PSBCh. 13.1 - Prob. 15PSBCh. 13.1 - Prob. 16PSBCh. 13.1 - Prob. 17PSBCh. 13.1 - Prob. 18PSBCh. 13.1 - Prob. 19PSBCh. 13.1 - Prob. 20PSBCh. 13.1 - Prob. 21PSCCh. 13.1 - Prob. 22PSCCh. 13.1 - Prob. 23PSCCh. 13.1 - Prob. 24PSCCh. 13.2 - Prob. 1PSACh. 13.2 - Prob. 2PSACh. 13.2 - Prob. 3PSACh. 13.2 - Prob. 4PSACh. 13.2 - Prob. 5PSACh. 13.2 - Prob. 6PSACh. 13.2 - Prob. 7PSACh. 13.2 - Prob. 8PSACh. 13.2 - Prob. 9PSBCh. 13.2 - Prob. 10PSBCh. 13.2 - Prob. 11PSBCh. 13.2 - Prob. 12PSBCh. 13.2 - Prob. 13PSBCh. 13.2 - Prob. 14PSBCh. 13.2 - Prob. 15PSBCh. 13.2 - Prob. 16PSBCh. 13.2 - Prob. 17PSBCh. 13.2 - Prob. 18PSBCh. 13.2 - Prob. 19PSBCh. 13.2 - Prob. 20PSCCh. 13.2 - Prob. 21PSCCh. 13.2 - Prob. 22PSCCh. 13.2 - Prob. 23PSCCh. 13.2 - Prob. 24PSCCh. 13.2 - Prob. 25PSCCh. 13.2 - Prob. 26PSCCh. 13.2 - Prob. 27PSCCh. 13.3 - Prob. 1PSACh. 13.3 - Prob. 2PSACh. 13.3 - Prob. 3PSACh. 13.3 - Prob. 4PSACh. 13.3 - Prob. 5PSBCh. 13.3 - Prob. 6PSBCh. 13.3 - Prob. 7PSBCh. 13.3 - Prob. 8PSBCh. 13.3 - Prob. 9PSBCh. 13.3 - Prob. 10PSBCh. 13.3 - Prob. 11PSBCh. 13.3 - Prob. 12PSBCh. 13.3 - Prob. 13PSCCh. 13.3 - Prob. 14PSCCh. 13.3 - Prob. 15PSCCh. 13.3 - Prob. 16PSCCh. 13.3 - Prob. 17PSCCh. 13.3 - Prob. 18PSCCh. 13.4 - Prob. 1PSACh. 13.4 - Prob. 2PSACh. 13.4 - Prob. 3PSACh. 13.4 - Prob. 4PSBCh. 13.4 - Prob. 5PSBCh. 13.4 - Prob. 6PSBCh. 13.4 - Prob. 7PSCCh. 13.4 - Prob. 8PSCCh. 13.4 - Prob. 9PSCCh. 13.5 - Prob. 1PSACh. 13.5 - Prob. 2PSACh. 13.5 - Prob. 3PSACh. 13.5 - Prob. 4PSACh. 13.5 - Prob. 5PSACh. 13.5 - Prob. 6PSACh. 13.5 - Prob. 7PSACh. 13.5 - Prob. 8PSACh. 13.5 - Prob. 9PSBCh. 13.5 - Prob. 10PSBCh. 13.5 - Prob. 11PSBCh. 13.5 - Prob. 12PSBCh. 13.5 - Prob. 13PSBCh. 13.5 - Prob. 14PSCCh. 13.5 - Prob. 15PSCCh. 13.5 - Prob. 16PSCCh. 13.5 - Prob. 17PSCCh. 13.6 - Prob. 1PSACh. 13.6 - Prob. 2PSACh. 13.6 - Prob. 3PSACh. 13.6 - Prob. 4PSACh. 13.6 - Prob. 5PSACh. 13.6 - Prob. 6PSACh. 13.6 - Prob. 7PSACh. 13.6 - Prob. 8PSACh. 13.6 - Prob. 9PSACh. 13.6 - Prob. 10PSACh. 13.6 - Prob. 11PSBCh. 13.6 - Prob. 12PSBCh. 13.6 - Prob. 13PSBCh. 13.6 - Prob. 14PSBCh. 13.6 - Prob. 15PSBCh. 13.6 - Prob. 16PSCCh. 13.6 - Prob. 17PSCCh. 13.6 - Prob. 18PSCCh. 13.6 - Prob. 19PSCCh. 13.6 - Prob. 20PSDCh. 13.7 - Prob. 1PSACh. 13.7 - Prob. 2PSACh. 13.7 - Prob. 3PSACh. 13.7 - Prob. 4PSACh. 13.7 - Prob. 5PSACh. 13.7 - Prob. 6PSACh. 13.7 - Prob. 7PSACh. 13.7 - Prob. 8PSACh. 13.7 - Prob. 9PSACh. 13.7 - Prob. 10PSACh. 13.7 - Prob. 11PSACh. 13.7 - Prob. 12PSACh. 13.7 - Prob. 13PSBCh. 13.7 - Prob. 14PSBCh. 13.7 - Prob. 15PSBCh. 13.7 - Prob. 16PSBCh. 13.7 - Prob. 17PSBCh. 13.7 - Prob. 18PSBCh. 13.7 - Prob. 19PSBCh. 13.7 - Prob. 20PSBCh. 13.7 - Prob. 21PSCCh. 13.7 - Prob. 22PSCCh. 13.7 - Prob. 23PSCCh. 13.7 - Prob. 24PSCCh. 13.7 - Prob. 25PSCCh. 13.7 - Prob. 26PSCCh. 13.7 - Prob. 27PSDCh. 13.7 - Prob. 28PSDCh. 13.7 - Prob. 29PSDCh. 13 - Prob. 1RPCh. 13 - Prob. 2RPCh. 13 - Prob. 3RPCh. 13 - Prob. 4RPCh. 13 - Prob. 5RPCh. 13 - Prob. 6RPCh. 13 - Prob. 7RPCh. 13 - Prob. 8RPCh. 13 - Prob. 9RPCh. 13 - Prob. 10RPCh. 13 - Prob. 11RPCh. 13 - Prob. 12RPCh. 13 - Prob. 13RPCh. 13 - Prob. 14RPCh. 13 - Prob. 15RPCh. 13 - Prob. 16RPCh. 13 - Prob. 17RPCh. 13 - Prob. 18RPCh. 13 - Prob. 19RPCh. 13 - Prob. 20RPCh. 13 - Prob. 21RPCh. 13 - Prob. 22RPCh. 13 - Prob. 23RPCh. 13 - Prob. 24RPCh. 13 - Prob. 25RPCh. 13 - Prob. 26RPCh. 13 - Prob. 27RPCh. 13 - Prob. 28RPCh. 13 - Prob. 29RPCh. 13 - Prob. 30RPCh. 13 - Prob. 31RPCh. 13 - Prob. 32RPCh. 13 - Prob. 33RPCh. 13 - Prob. 34RPCh. 13 - Prob. 35RPCh. 13 - Prob. 36RPCh. 13 - Prob. 37RP
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