Chapter 13.5, Problem 10PSB

To determine

To find:The point in point-slope form for the equation of JP.

Answer to Problem 10PSB

The equation in point slope form is $y-6=\frac{1}{6}\left(x-5\right)$ .

Explanation of Solution

Given:

The point is given as,

  $P=\left(3,5\right)$

Calculation:

The P is 2 units to the right of x=1,

So, the coordinates of P’ is,

  $\begin{array}{c}P\text{'}=\left(1-2,5\right)\\ =\left(-1,5\right)\end{array}$

Then,

  $\begin{array}{c}m\left(JP\text{'}\right)=\frac{6-5}{5-\left(-1\right)}\\ =\frac{1}{6}\end{array}$

Now, the equation of line in point slope form.

  $y-6=\frac{1}{6}\left(x-5\right)$

Thus, the equation in point slope form is $y-6=\frac{1}{6}\left(x-5\right)$ .