Chapter 13.7, Problem 5PSA

(a)

To determine

To find:The measure of OM.

Answer to Problem 5PSA

The measure of OM is $5\text{units}$ .

Explanation of Solution

Consider the figure shown below.\

  

The length $EF$ is calculated as,

  $\begin{array}{c}EF=\sqrt{8^2+6^2}\\ =\sqrt{100}\\ =10\text{unit}\end{array}$

M is the midpoint of EF . So,

  $\begin{array}{c}EM=EF\\ =5\text{units}\end{array}$

By similar triangle property.

  $OM=EM=MF$

The measure of OM is $\text{5}\text{units}$ .

(b)

To determine

To find: The measure of MF.

Answer to Problem 5PSA

The measure of EM is $5\text{units}$ .

Explanation of Solution

  $\begin{array}{c}EF=\sqrt{8^2+6^2}\\ =\sqrt{100}\\ =10\text{unit}\end{array}$

M is the midpoint of EF . So,

  $\begin{array}{c}EM=MF\\ =5\text{units}\end{array}$

By similar triangle property.

  $OM=EM=MF$

The measure of EM is $\text{5}\text{units}$ .

(c)

To determine

To find: The measure of MF.

Answer to Problem 5PSA

The measure of MF is $5\text{units}$ .

Explanation of Solution

  $\begin{array}{c}EF=\sqrt{8^2+6^2}\\ =\sqrt{100}\\ =10\text{unit}\end{array}$

M is the midpoint of EF . So,

  $\begin{array}{c}EM=MF\\ =5\text{units}\end{array}$

By similar triangle property.

  $OM=EM=MF$

The measure of MF is $\text{5}\text{units}$ .