Chapter 13.5, Problem 13.5BFP

Interpretation Introduction

Interpretation:

The mass percent and the mole fraction of ethanol, iso-octane, and heptane are to be calculated.

Concept introduction:

Mass percent is defined as the mass of a component divided by the total mass of the mixture, multiplied by 100.

The mole fraction is defined as the ratio of the number of moles of solute to the total number of moles in the mixture, multiplied by 100. It is represented by $\text{X}$.

The formula to calculate the mole percent is as follows:

$\text{Mole}\text{percent}=\left(\frac{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}}{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}+\text{amount}\left(\text{mol}\right)\text{of}\text{solvent}}\right)100$ (1)