Chapter 13, Problem 13.57P

(a)

Interpretation Introduction

Interpretation:

The molarity of the aqueous solution of $0.82\text{g}$ of ethanol in $10.5\text{mL}$ of solution is to be determined.

Concept introduction:

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by $M$ and its unit is $\text{mol/L}$.

The formula to calculate the molarity of the solution is as follows:

$\text{Molarity}=\frac{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}}{\text{volume }\left(\text{L}\right)\text{of}\text{}\text{solution}}$ (1)

(b)

Interpretation Introduction

Interpretation:

The molarity of the aqueous solution of $1.27\text{g}$ of gaseous ${\text{NH}}_3$ in $33.5\text{mL}$ of solution is to be determined.

Concept introduction:

Molarity is defined as the number of moles of solute that are dissolved in one litre of solution. It is represented by $M$ and its unit is $\text{mol/L}$.

The formula to calculate the molarity of the solution is as follows:

$\text{Molarity}=\frac{\text{amount}\left(\text{mol}\right)\text{of}\text{solute}}{\text{volume }\left(\text{L}\right)\text{of}\text{}\text{solution}}$ (1)