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(a)
Interpretation: The chemical formulas for the ribose and Deoxyribose sugars have to be given.
Concept Introduction:
Concept of
- • Nucleic acids are biopolymers that are essential to all forms of life.
- • The nucleic acid is composed of
nucleotides. - • The nucleotides are composed of monomers.
- • The monomers are made of three components such as 5-carbon sugar, a phosphate group and a nitrogenous base.
- • The 5-carbon sugar can be ribose or deoxyribose sugar.
- • If the 5-carbon sugar is a ribose unit, then the overall nucleic acid is known as ribose nucleic acid which is abbreviated as RNA.
- • If the 5-carbon sugar is a deoxyribose unit, then the overall nucleic acid is known as deoxyribose nucleic acid which is abbreviated as DNA.
(b)
Interpretation:
The structural formulas of the ribose and deoxyribose sugars have to be differentiated.
Concept Introduction:
Concept of Nucleic acids:
- • Nucleic acids are biopolymers that are essential to all forms of life.
- • The nucleic acid is composed of nucleotides.
- • The nucleotides are composed of monomers.
- • The monomers are made of three components such as 5-carbon sugar, a phosphate group and a nitrogenous base.
- • The 5-carbon sugar can be ribose or deoxyribose sugar.
- • If the 5-carbon sugar is a ribose unit, then the overall nucleic acid is known as ribose nucleic acid which is abbreviated as RNA.
- • If the 5-carbon sugar is a deoxyribose unit, then the overall nucleic acid is known as deoxyribose nucleic acid which is abbreviated as DNA.
(c)
Interpretation:
Whether the given ribose and deoxyribose formulas fit with the given formula pattern of carbohydrate or not has to be found.
Concept Introduction:
Concept of Nucleic acids:
- • Nucleic acids are biopolymers that are essential to all forms of life.
- • The nucleic acid is composed of nucleotides.
- • The nucleotides are composed of monomers.
- • The monomers are made of three components such as 5-carbon sugar, a phosphate group and a nitrogenous base.
- • The 5-carbon sugar can be ribose or deoxyribose sugar.
- • If the 5-carbon sugar is a ribose unit, then the overall nucleic acid is known as ribose nucleic acid which is abbreviated as RNA.
- • If the 5-carbon sugar is a deoxyribose unit, then the overall nucleic acid is known as deoxyribose nucleic acid which is abbreviated as DNA.
Carbohydrates are the sugars that are found in the basic food and provide energy to the human bond to perform various works.
(d)
Interpretation: In the ribose and deoxyribose sugar units, the atoms that would form hydrogen bonds with water or other nucleic acids are to be shown.
Concept Introduction:
Hydrogen bonding:
- • Hydrogen bonding is a special type of dipole-dipole interaction in a polar bond which has hydrogen atom and a highly electronegative atom such as Nitrogen, Oxygen and Fluorine.
- • Hydrogen bonding can also be defined as coulombic attraction between the hydrogen atom and an electronegative atom.
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Chapter 13 Solutions
Chemistry In Context
- Please correct answer and don't use hand ratingarrow_forwardSafari File Edit View History Bookmarks Window Help く < mylabmastering.pearson.com Wed Feb 12 8:44 PM ✩ + Apple Q Bing Google SignOutOptions M Question 36 - Lab HW BI... P Pearson MyLab and Mast... P Course Home Error | bartleby b Answered: If the biosynth... Draw a free-radical mechanism for the following reaction, forming the major monobromination product: ScreenPal - 2022 CHEM2... Access Pearson 2 CH3 Br-Br CH H3 Draw all missing reactants and/or products in the appropriate boxes by placing atoms on the canvas and connecting them with bonds. Add charges where needed. Electron- flow arrows should start on the electron(s) of an atom or a bond and should end on an atom, bond, or location where a new bond should be created. Include all free radicals by right-clicking on an atom on the canvas and then using the Atom properties to select the monovalent radical. ▸ View Available Hint(s) 0 2 DE [1] H EXP. CONT. H. Br-Br H FEB 12arrow_forwardPlease correct answer and don't use hand ratingarrow_forwardNonearrow_forwardQ1: For each molecule, assign each stereocenter as R or S. Circle the meso compounds. Label each compound as chiral or achiral. + CI Br : Н OH H wo་ཡིག་ཐrow HO 3 D ။။ဂ CI Br H, CI Br Br H₂N OMe R IN I I N S H Br ជ័យ CI CI D OHarrow_forwardPlease correct answer and don't use hand ratingarrow_forwardNonearrow_forward%Reflectance 95 90- 85 22 00 89 60 55 50 70 65 75 80 50- 45 40 WA 35 30- 25 20- 4000 3500 Date: Thu Feb 06 17:21:21 2025 (GMT-05:0(UnknownD Scans: 8 Resolution: 2.000 3000 2500 Wavenumbers (cm-1) 100- 2981.77 1734.25 2000 1500 1000 1372.09 1108.01 2359.09 1469.82 1181.94 1145.20 1017.01 958.45 886.97 820.49 668.25 630.05 611.37arrow_forwardNonearrow_forwardCH3 CH H3C CH3 H OH H3C- -OCH2CH3 H3C H -OCH3 For each of the above compounds, do the following: 1. List the wave numbers of all the IR bands in the 1350-4000 cm-1 region. For each one, state what bond or group it represents. 2. Label equivalent sets of protons with lower-case letters. Then, for each 1H NMR signal, give the 8 value, the type of splitting (singlet, doublet etc.), and the number protons it represents. of letter δ value splitting # of protons 3. Redraw the compound and label equivalent sets of carbons with lower-case letters. Then for each set of carbons give the 5 value and # of carbons it represents. letter δ value # of carbonsarrow_forwardDraw the correct ionic form(s) of arginine at the pKa and PI in your titration curve. Use your titration curve to help you determine which form(s) to draw out.arrow_forwardPlease correct answer and don't use hand ratingarrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
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