Explanation Given information: The density of the spherical planet is ρ . The minimum time period is a time required to the satellite to complete one revolution around a spherical planet. Formula to calculate the minimum time period for a satellite is, T min = 2 π R v (I) R is the radius of the planet. v is the orbital velocity Formula to calculate the orbital velocity is, v = G M R (II) M is the mass of the spherical planet. G is the universal gravitational constant. Formula to calculate mass of the spherical planet is, M = ρ × 4 3 π R 3 ρ is the density of a spherical planet. Substitute ρ × 4 3 π R 3 for M in equation (II)

Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)

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Chapter 13, Problem 72AP

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To show: The minimum period for a satellite is Tmin=3πGρ .

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Physics for Scientists and Engineers with Modern, Revised Hybrid (with Enhanced WebAssign Printed Access Card for Physics, Multi-Term Courses)

Ch. 13.1 - A planet has two moons of equal mass. Moon 1 is in...Ch. 13.2 - Prob. 13.2QQ Ch. 13.4 - Prob. 13.3QQ Ch. 13.6 - Prob. 13.4QQ Ch. 13 - Prob. 1OQ Ch. 13 - Prob. 2OQ Ch. 13 - Prob. 3OQ Ch. 13 - Prob. 4OQ Ch. 13 - Prob. 5OQ Ch. 13 - Prob. 6OQ

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