Chemistry: Structure and Properties Custom Edition for Rutgers University General Chemistry
15th Edition
ISBN: 9781269935678
Author: Nivaldo J. Tro
Publisher: Pearson Education
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Chapter 13, Problem 6E
What is a crystalline lattice? How is the lattice represented with the unit cell?
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Chapter 13 Solutions
Chemistry: Structure and Properties Custom Edition for Rutgers University General Chemistry
Ch. 13 - Determine what state this substance is in at 1 atm...Ch. 13 - Prob. 2SAQCh. 13 - Prob. 3SAQCh. 13 - Prob. 4SAQCh. 13 - Prob. 5SAQCh. 13 - Prob. 6SAQCh. 13 - Prob. 7SAQCh. 13 - Prob. 8SAQCh. 13 - Prob. 9SAQCh. 13 - Prob. 10SAQ
Ch. 13 - What is a phase diagram?Ch. 13 - Draw a generic phase diagram and label its...Ch. 13 - What is the significance of crossing a line in a...Ch. 13 - What is graphene? Why is graphene unique?Ch. 13 - Prob. 5ECh. 13 - What is a crystalline lattice? How is the lattice...Ch. 13 - Prob. 7ECh. 13 - Prob. 8ECh. 13 - What is the difference between hexagonal closest...Ch. 13 - What are the three basic types of solids and the...Ch. 13 - Prob. 11ECh. 13 - What kinds of forces hold each of the three basic...Ch. 13 - Prob. 13ECh. 13 - Prob. 14ECh. 13 - Prob. 15ECh. 13 - Prob. 16ECh. 13 - Prob. 17ECh. 13 - Prob. 18ECh. 13 - Prob. 19ECh. 13 - Consider the phase diagram for iodine shown here....Ch. 13 - Prob. 21ECh. 13 - Prob. 22ECh. 13 - Prob. 23ECh. 13 - Prob. 24ECh. 13 - Prob. 25ECh. 13 - An X-ray beam of unknown wavelength is diffracted...Ch. 13 - Prob. 27ECh. 13 - Determine the coordination number for each...Ch. 13 - Prob. 29ECh. 13 - Molybdenum crystallizes with the body-centred unit...Ch. 13 - Prob. 31ECh. 13 - An atom has a radius of 142 pm and crystallizes in...Ch. 13 - Rhodium has a density of 12.41 g / cm3 and...Ch. 13 - Barium has a density of 3.59 g/cm3 and...Ch. 13 - Prob. 35ECh. 13 - Palladium crystallizes with a face-centered cubic...Ch. 13 - Prob. 37ECh. 13 - Identify each solid as molecular, ionic, or...Ch. 13 - Which solid has the highest melting point? Why?...Ch. 13 - Which solid has the highest melting point? Why?...Ch. 13 - Which solid in each pair has the higher melting...Ch. 13 - Which solid in each pair has the higher melting...Ch. 13 - Prob. 43ECh. 13 - Prob. 44ECh. 13 - Prob. 45ECh. 13 - Prob. 46ECh. 13 - The unit cells for cesium chloride and barium(ll)...Ch. 13 - Prob. 48ECh. 13 - Prob. 49ECh. 13 - Prob. 50ECh. 13 - Prob. 51ECh. 13 - Prob. 52ECh. 13 - Prob. 53ECh. 13 - Prob. 54ECh. 13 - Prob. 55ECh. 13 - Prob. 56ECh. 13 - Prob. 57ECh. 13 - The density of an unknown metal is 12.3 g/cm3 and...Ch. 13 - Prob. 59ECh. 13 - Consider a planet where the pressure of the...Ch. 13 - An unknown metal is found to have a density of...Ch. 13 - Prob. 62ECh. 13 - Potassium chloride crystallizes in the rock salt...Ch. 13 - Calculate the fraction of empty space in cubic...Ch. 13 - Prob. 65ECh. 13 - Prob. 66ECh. 13 - Prob. 67E
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- An amorphous solid can sometimes be converted to a crystalline solid by a process called annealing. Annealing consists of heating the substance to a temperature just below the melting point of the crystalline form and then cooling it slowly. Explain why this process helps produce a crystalline solid.arrow_forwardWhy is the C 60form of carbon called buckminsterfullerene?arrow_forward(a) Determining an Atom Radius from Lattice Dimensions: Gold has a face-centered unit cell, and its density is 19.32 g/cm3. Calculate the radius of a gold atom. (b) The Structure of Solid Iron: Iron has a density of 7.8740 g/cm3, and the radius of an iron atom is 126 pm. Verify that solid iron has a body-centered cubic unit cell. (Be sure to note that the atoms in a body-centered cubic unit cell touch along the diagonal across the cell. They do not touch along the edges of the cell.) (Hint: The diagonal distance across the unit cell = edge 3.)arrow_forward
- The unit cell for nickel arsenide is shown below. What is the formula of this compound?arrow_forwardThe structures of some common crystalline substances are shown below. Show that the net composition of each unit cell corresponds to the correct formula of each substance.arrow_forwardThe CsCl structure is a simple cubic array of chloride ions with a cesium ion at the center of each cubic array (see Exercise 69). Given that the density of cesium chloride is 3.97 g/cm3, and assuming that the chloride and cesium ions touch along the body diagonal of the cubic unit cell, calculate the distance between the centers of adjacent Cs+ and Cl ions in the solid. Compare this value with the expected distance based on the sizes of the ions. The ionic radius of Cs+ is 169 pm, and the ionic radius of Cl is 181 pm.arrow_forward
- • describe the arrangement of atoms in the common cubic crystal lattices and calculate the packing efficiency for a lattice.arrow_forwardDescribe the crystal structure of iron, which crystallizes with two equivalent metal atoms in a cubic unit cell.arrow_forwardAssume X has a body-centered cubic lattice with all atoms at the lattice points. The edge length of the unit cell is 379.0 pm. The atomic mass of X is 195.0 amu. Calculate the density of X.arrow_forward
- Silicon carbide, SiC, is a very hard, high-melting solid. What kind of crystal forces account for these properties?arrow_forwardPhase diagrams for materials that have allotropes can be more complicated than those shown in the chapter. Use the phase diagram for carbon given here to answer the following questions. (a) How many triple points are present and what phases are in equilibrium for each? (b) Is there a single point where all four phases are in equilibrium? (c) Which is more stable at high pressures, diamond or graphite? (d) Which is the stable phase of carbon at room temperature and 1 atmosphere pressure?arrow_forwardCalculate the percent of volume that is actually occupied by spheres in a body-centered cubic lattice of identical spheres You can do this by first relating the radius of a sphere, r, to the length of an edge of a unit cell, l. (Note that the spheres do not touch along an edge but do touch along a diagonal passing through the body-centered sphere.) Then calculate the volume of a unit cell in terms of r. The volume occupied by spheres equals the number of spheres per unit cell times the volume of a sphere (4r3/3).arrow_forward
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