Carbon show unique properties, it forms very large no. of molecule. Catenation is the linkage of atom of the same element in to long chain, this property dominate in carbon atom. Due to which carbon forms very large no. of compound. Carbon is capable of forming many allotropes due to its valency. Well known forms of carbon include diamond and graphite. Concept introduction: In diamond all the carbon atoms have strong chemical bonds to four other carbon atoms, making perfect tetrahedral on and on throughout the crystal. In graphite all the carbon atoms have strong chemical bonds to three other carbon atoms making sheets that look like chicken wire, weak forces hold the sheets to gether hybridisation of carbon atom in graphite is s p 2 , But in diamond is s p 3 . To determine: Explain why the graphite structure of carbon allows graphite to be used as a lubricant, but the diamond structure of carbon does not.

Question

Want to see the full answer?

Answer 1

Question

Chapter 13, Problem 49E

Interpretation Introduction

Interpretation:

Carbon show unique properties, it forms very large no. of molecule. Catenation is the linkage of atom of the same element in to long chain, this property dominate in carbon atom. Due to which carbon forms very large no. of compound. Carbon is capable of forming many allotropes due to its valency. Well known forms of carbon include diamond and graphite.

Concept introduction:

In diamond all the carbon atoms have strong chemical bonds to four other carbon atoms, making perfect tetrahedral on and on throughout the crystal.

In graphite all the carbon atoms have strong chemical bonds to three other carbon atoms making sheets that look like chicken wire, weak forces hold the sheets to gether hybridisation of carbon atom in graphite is $s p^{2}$ , But in diamond is $s p^{3}$ .

To determine:

Explain why the graphite structure of carbon allows graphite to be used as a lubricant, but the diamond structure of carbon does not.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Predicting edict the major products of this organic reaction. If there aren't any products, because nothing will happen, check the box under the drawing area instead. + No reaction. Explanation Check HO Na O H xs H₂O 2 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center I

Choosing reagents and conditions for acetal formation or hydrolysis 0/5 A student proposes the transformation below in one step of an organic synthesis. There may be one or more products missing from the right-hand side, but there are no reagents missing from the left-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. If the student's transformation is possible, then complete the reaction by adding any missing products to the right-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + This transformation can't be done in one step. 5 I H Autumn alo 值 Ar B

A block of copper of mass 2.00kg(cp = 0.3851 .K) and g temperature 0°C is introduced into an insulated container in which there is 1.00molH, O(g) at 100°C and 1.00 2 atm. Note that C P = 4.184. K for liquid water, and g that A H = 2260 for water. vap g Assuming all the steam is condensed to water, and that the pressure remains constant: (a) What will be the final temperature of the system? (b) What is the heat transferred from the water to the copper? (c) What is the entropy change of the water, the copper, and the total system?