Chapter 13, Problem 68P

To determine

To find: The estimated pressure inside the pressure cooker.

Answer to Problem 68P

Pressure inside the cooker is $1.99\times {10}^5\text{Pa}=1.97\text{atm}$ .

Explanation of Solution

Introduction:

Saturated pressure is that pressure where the no. of the molecules in the vapor phase is equal to the no. of the molecule in the liquid phase until the liquid reached the equilibrium.

Saturated water vapor pressure of the water is ${120}^0\text{C}$ . And the pressure inside the pressure cooker is same as the saturated pressure. And the value is $1.99\times {10}^5\text{Pa}=1.97\text{atm}$ . Saturated pressure of the water is same as the pressure inside the cooker.

Conclusion:

Pressure inside the cooker is $1.99\times {10}^5\text{Pa}=1.97\text{atm}$ .