Chapter 13, Problem 62P

To determine

To Calculate:The phase of the water when the temperature and pressure is given.

Answer to Problem 62P

Vapor Phase

Explanation of Solution

Given:

Pressure= $0.01\text{atm}$

Temperature= ${90}^0\text{C}$

At ${90}^0\text{C}$ temperature and $0.01\text{atm}$ pressurethe water is in vapor phase. This can be explaining from the phase diagram of the water. Phase diagram is the graphical representation of the physical state of the matter. In phase diagram the x-axis represents the temperature curve and y-axis represent the pressure curve.

Conclusion:

Water exist in vapor phase at $0.01\text{atm}$ pressure and ${90}^0\text{C}$ temperature.

(b)

To determine

To Calculate:The phase of the water when the temperature and pressure is given.

Answer to Problem 62P

Solid phase

Explanation of Solution

Given:

Pressure= $0.01\text{atm}$

Temperature= $-{20}^0\text{C}$

At $-{20}^0\text{C}$ temperature and $0.01\text{atm}$ pressure the water is in solid phase. This can be explaining from the phase diagram of the water. Phase diagram is the graphical representation of the physical state of the matter. In phase diagram the x-axis represents the temperature curve and y-axis represent the pressure curve.

Conclusion:

The water exist in solid phase at $-{20}^0\text{C}$ temperature and pressure $0.01\text{atm}$.