Chapter 13, Problem 26P

(a)

To determine

The temperature on the Kelvin scale.

Answer to Problem 26P

  $359.15\text{K}$

Explanation of Solution

Given:

The temperature, $T\left(\text{°C}\right)={86}^{\text{o}}\text{C}$

Formula used:

Write the expression for the temperature conversion from degree Celsius to Kelvin.

  $T(\text{K})=T(°\text{C})+273.15$

Calculation:

Substitute the values in the above expression.

  $\begin{array}{c}T(\text{K})=T(\text{°C})+273.15\\ =86+273.15\\ =359.15\text{K}\end{array}$

Conclusion:

After the conversion of degree Celsius in Kelvin, the temperature becomes $359.15\text{K}$ .

(b)

To determine

The temperature on the Kelvin scale.

Answer to Problem 26P

  $298.7\text{K}$

Explanation of Solution

Given:

The temperature is $78\text{°F}$ .

Calculation:

Write the expression for the conversion of temperature from kelvin to Fahrenheit.

  $T(\text{K})=\frac{5}{9}[T{(}^{\text{o}}\text{F})-32]+273.15$

  $\begin{array}{c}T(\text{K})=\frac{5}{9}[T{(}^{\text{o}}\text{F})-32]+273.15\\ =\frac{5}{9}[78-32]+273.15\\ =298.7\text{K}\end{array}$

Conclusion:

The temperature on Kelvin scale is $298.7\text{K}$ .

(c)

To determine

The temperature on the Kelvin scale.

Answer to Problem 26P

  $173.15\text{K}$

Explanation of Solution

Given:

The temperature is $100°\text{C}$ .

Formula used:

Write the expression for the temperature conversion from the degree Celsius to kelvin.

  $T(\text{K})=T(°\text{C})+273.15$

Calculation:

Substitute the values in the above expression.

  $\begin{array}{c}T(\text{K})=T(°\text{C})+273.15\\ =-100+273.15\\ =173.15\text{K}\end{array}$

Conclusion:

The temperature on kelvin scale is $173.15\text{K}$ .

(d)

To determine

The temperature on the Kelvin scale.

Answer to Problem 26P

  $5773.15\text{K}$

Explanation of Solution

Given:

The temperature is $5500\text{°C}$ .

Formula:

Write the expression for the conversion of temperature from degree Celsius to Kelvin.

  $T(\text{K})=T(\text{°C})+273.15$

Calculation:

Substitute the values in the above the expression.

  $\begin{array}{c}T(\text{K})=T(\text{°C})+273.15\\ =5500+273.15\\ =5773.15\text{K}\end{array}$

Conclusion:

The temperature becomes $5773.15\text{K}$ on the Kelvin scale.

(e)

To determine

Answer to Problem 26P

  $0.37\text{K}$

Explanation of Solution

Given: The temperature on Fahrenheit scale is $-459\text{°F}$ .

Formula used:

Write the expression for the temperature conversion to the Kelvin.

  $T(\text{K})=\frac{5}{9}[T(°\text{F})-32]+273.15$

Calculation:

  $\begin{array}{l}T(\text{K})=\frac{5}{9}[T(°\text{F})-32]+273.15\\ =\frac{5}{9}[-459-32]+273.15\\ =0.37\text{K}\end{array}$

Conclusion:

The temperature on the Kelvin scale is $0.\text{37}\text{K}$ .