From the given standard enthalpies, the N-H bond energy needs to be determined. Concept Introduction: For a reaction, the change in enthalpy can be calculated from bond dissociation energy as follows: Δ H = ∑ B . E ( Reactant ) − ∑ B . E ( Product ) That is the difference of total energy of bond broken and total energy of bond formed. Also, from standard enthalpy of formation, the change in enthalpy of reaction is calculated as follows: Δ H = ∑ Δ H ( Product ) − ∑ Δ H ( Reactant )

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Answer 1

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Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 13, Problem 61E

Interpretation Introduction

Interpretation: From the given standard enthalpies, the N-H bond energy needs to be determined.

Concept Introduction: For a reaction, the change in enthalpy can be calculated from bond dissociation energy as follows:

ΔH=∑B.E(Reactant)−∑B.E(Product)

That is the difference of total energy of bond broken and total energy of bond formed. Also, from standard enthalpy of formation, the change in enthalpy of reaction is calculated as follows:

ΔH=∑ΔH(Product)−∑ΔH(Reactant)

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1. Consider these three reactions as the elementary steps in the mechanism for a chemical reaction. 2600 2400 2200 2000 1800 1600 1400 1200 1000 800 Potential Energy (kJ) 600 400 200 0 -200- -400 -600- -800 (i) Cl₂ (g) + Pt(s) → 2Cl (g) + Pt(s) (ii) Cl (g)+ CO (g) + Pt (s) → CICO (g) + Pt (s) Ea = 1550 kJ Ea = 2240 kJ (iii) Cl (g) + CICO (g) → Cl₂CO (g) Ea = 2350 kJ AH=-950 kJ ΔΗ = 575 ΚΙ AH=-825 kJ a. Draw the potential energy diagram for the reaction. Label the data points for clarity. The potential energy of the reactants is 600 kJ Reaction Progress b. What is the overall chemical equation? c. What is the overall change in enthalpy for the above chemical reaction? d. What is the overall amount of activation energy for the above chemical reaction? e. Which reaction intermediate would be considered a catalyst (if any) and why? f. If you were to add 2700kJ of energy to the reaction (e.g. 2700 kl of heat or electricity), would you be able to make the reaction reverse itself (i.e. have…

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Answer 2

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Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 13, Problem 61E

Interpretation Introduction

Interpretation: From the given standard enthalpies, the N-H bond energy needs to be determined.

Concept Introduction: For a reaction, the change in enthalpy can be calculated from bond dissociation energy as follows:

ΔH=∑B.E(Reactant)−∑B.E(Product)

That is the difference of total energy of bond broken and total energy of bond formed. Also, from standard enthalpy of formation, the change in enthalpy of reaction is calculated as follows:

ΔH=∑ΔH(Product)−∑ΔH(Reactant)

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Answer 3

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 13, Problem 61E

Interpretation Introduction

Interpretation: From the given standard enthalpies, the N-H bond energy needs to be determined.

Concept Introduction: For a reaction, the change in enthalpy can be calculated from bond dissociation energy as follows:

ΔH=∑B.E(Reactant)−∑B.E(Product)

That is the difference of total energy of bond broken and total energy of bond formed. Also, from standard enthalpy of formation, the change in enthalpy of reaction is calculated as follows:

ΔH=∑ΔH(Product)−∑ΔH(Reactant)

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 4

Question

Formula Formula Bond dissociation energy (BDE) is the energy required to break a bond, making it an endothermic process. BDE is calculated for a particular bond and therefore consists of fragments such as radicals since it undergoes homolytic bond cleavage. For the homolysis of a X-Y molecule, the energy of bond dissociation is calculated as the difference in the total enthalpy of formation for the reactants and products. X-Y → X + Y BDE = Δ H f X + Δ H f Y – Δ H f X-Y where, ΔHf is the heat of formation.

Chapter 13, Problem 61E

Interpretation Introduction