Chapter 13, Problem 41E

Consider the following: $\text{Li(}s\text{)+}\frac{1}{2}{\text{I}}_{\text{2}}\text{(}g\text{)}\to \text{LiI(}s\text{)}\Delta H\text{= -292 kJ}$ . LiI(s) has a lattice energy of 2753 kJ/mol. The ionization energy of Li(g) is 520. kJ/mol, the bond energy of ${\text{I}}_2(g)$ is 151 kJ/mol, and the electron affinity of I(g) is -295 kJ/mol. Use these data to determine the heat
of sublimation of Li(s).