Biology: The Unity and Diversity of Life
15th Edition
ISBN: 9780357093795
Author: STARR
Publisher: CENGAGE LEARNING (CUSTOM)
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 13, Problem 5GP
Summary Introduction
To explain: The probability that one of the surviving kittens with parents having the allele MLM associated with taillessness in Manx cats will be heterozygous.
Concept introduction: The mutated ML allele is associated with taillessness in Manx cats. The homozygous MLML allele is called as lethal alleles, as they cause death of the kitten as embryo itself due to defects of the spinal cord. Lethal alleles are those in heterozygous or homozygous form that causes death of the individual during embryonic development itself. The probability reduces in such cases, as those alleles will not be transferred to the next generation as the allele is lost with the death of the embryo.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
In fruit flies, the dominant H allele gives rise to a hairless phenotype, hh gives rise to normal body bristles, and the HH homozygote condition is lethal during an embryonic stage. The presence of a dominant S allele suppresses the effect of the dominat H allele with respect to the body bristles phenotype such that normal body bristle phenotype is restored when only one dominant H allele is present (HH is lethal irrespective of the S or s alleles). The ss genotype has no effect over the H allele and the SS homozygote condition is also lethal during an embryonic stage. What would be the expected phenotypic outcomes among the surviving offspring from the following cross:
HhSs X hhSs
2 normal body bristles: 1 hairless
7 normal body bristles: 2 hairless
1 normal body bristles: 1 hairless
3 normal body bristles: 1 hairless
5 normal body bristles: 1 hairless
The ABO blood groups in humans are expressed as the IA, IB, and i alleles. The IA allele encodes the A blood group antigen, IB encodes B, and i encodes O. Both A and B are dominant to O. If a heterozygous blood type A parent (IAi) and a heterozygous blood type B parent (IBi) mate, one quarter of their offspring will have AB blood type (IAIB) in which both antigens are expressed equally. Therefore, ABO blood groups are an example of: a. multiple alleles and incomplete dominance b. codominance and incomplete dominance c. incomplete dominance only d. multiple alleles and codominance
In the Manx tailless phenotype of cats, the tailless phenotype is caused by the mutation ML and is inherited as an autosomal dominant trait. Homozygotes for ML are lethal, and do not survive to birth. A breeder mates a Manx tailless male with a Manx tailless female. The female is now pregnant with a litter of 3 kittens.
What is the probability that all the kittens born will be tailless?
0.012
0.125
0.04
0.20
0.30
Chapter 13 Solutions
Biology: The Unity and Diversity of Life
Ch. 13 - Prob. 1DAACh. 13 - Prob. 2DAACh. 13 - Prob. 3DAACh. 13 - Prob. 1SQCh. 13 - An organisms observable traits constitute its...Ch. 13 - Prob. 3SQCh. 13 - Prob. 4SQCh. 13 - The offspring of the cross AA aa are ________. a....Ch. 13 - Refer to question 5. Assuming complete dominance,...Ch. 13 - A testcross is a way to determine ________. a....
Ch. 13 - Assuming complete dominance, a cross between...Ch. 13 - The probability of a crossover occurring between...Ch. 13 - True or false? All traits are inherited in a...Ch. 13 - One gene that affects three traits is an example...Ch. 13 - The phenotype of individuals heterozygous for...Ch. 13 - _______ in a trait is indicated by a bell curve....Ch. 13 - Match the terms with the best description. ______...Ch. 13 - Mendel crossed a true-breeding pea plant with...Ch. 13 - Assuming that independent assortment occurs during...Ch. 13 - Refer to problem 2. Determine the predicted...Ch. 13 - For each genotype listed, what allele combinations...Ch. 13 - Prob. 5GPCh. 13 - Suppose you identify a new gene in mice. One of...Ch. 13 - Mutations in the TYR gene may render its enzyme...Ch. 13 - In sweet pea plants, an allele for purple flowers....Ch. 13 - Red-flowering snapdragons are homozygous for...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?arrow_forwardIn mice, the A allele causes agouti fur, the AY allele causes yellow fur and is dominant to the A allele. The homozygous AY AY genotype is lethal. Why is the AYAY homozygous condition lethal? The AY allele highly transcribes the merc gene which is lethal in a homozygous AYAY individual. None of the other answers are correct. The AY allele lacks an upstream merc gene which is required for normal embryonic development. The AY allele contains a null mutation in the A gene, which is required for normal embryonic development. The yellow pigment produced by A allele is required for survival.arrow_forwardGlucose-6-phosphate dehydrogenase (G6PD)-deficiency is another human red blood cell disease that affects 400,000 individuals worldwide every year as a result of a defective allele of the G6PD enzyme. This disorder results in crippling and sometimes fatal anemia in individuals when induced by stress, certain medications, foods (e.g. fava beans), or infection. (G6PD)-deficiency is a single-gene recessive X-linked trait. If an unaffected couple gives birth to a son with G6PD-deficiency disorder, what is the likelihood that their next child, who will be a daughter, will suffer from (G6PD)-deficiency disorder? 0% 25% 50% 75% 100%arrow_forward
- Consider the following scenario: A man without freckles (freckles are a dominant trait, determined by the dominant allele “F”) is a carrier of cystic fibrosis (recall that CF is a recessive trait, determined by the recessive allele "a"), mates with a woman whose genotype is heterozygous for freckles and is also a carrier of CF. Assume the two genes in question are in different chromosomes and, therefore, assort independently. Complete the following Punnett square to generate the offspring probabilities from this couple, by entering the genotypes of the parents, the gametes, and the offspring for the two traits described above. (4) Father’s genotype ffAa Mother’s genotypeFfAa ● Sperm: fA ● Sperm: fa ● Sperm: fA ● Sperm: fa ● Egg: FA ● Egg: fA ● Egg: Fa ● Egg: fa What is the probability for this couple to have a child with freckles? What is the…arrow_forwardGive nine examples of lethal alleles in humans, other animals, and plants and a brief molecular explanation (i.e., why are they lethal).arrow_forwardABO blood type is determined by three alleles: *, 18, and i. On a separate chromosome, anotherset of alleles determines the Rhesus factor: D and d.A woman with blood type A, who is heterozygous for both blood type and Rhesus factor, had achild with a man with blood type B, who is heterozygous for both blood type and Rhesus factor. What is the percentage chance that this child is blood type B and heterozygous for both traits? Record your answer as a percentage rounded to one decimal place.arrow_forward
- A homozygous recessive allele, aa, is responsible for albinism. Humans can exhibit this phenotype. In each of the following cases, determine the possible genotypes of the mother and father, and of their children: (a) Both parents have normal phenotypes; some of their children are albino and others are unaffected: (b) Both parents are albino and have only albino children: (c) The woman is unaffected, the man is albino, and they have one albino child and three unaffected children: at a busy hospital. The son of the first couple has hemophilia, a recessive, X-linked Two mothers give birth to sor disease. Neither parent from couple #1 has the disease. The second couple has an unaffected son, despite the fact that the father has hemophilia. The two couples challenge the hospital in court, claiming their babies must have beer swapped at birth. You must advise as to whether or not the sons could have been swapped. What would you say? 5. In a dispute over parentage, the mother of a child with…arrow_forwardIn humans, a widow’s peak hairline (H) has complete dominance over the straight hairline (h).What is the genotype for an individual that homozygous dominant for this traitarrow_forwardA recessive epistasis cross gives in the F2 a 9:3:4 phenotypic ratio. What is the expected phenotypic ratio when the F1 (BbEe) is crossed with the double recessive homozygote (bbee)? Keeping in mind ee masks the expression of B.arrow_forward
- A dominant genetic factor P is required for the formation of an enzyme needed to convert phenylalanine to tyrosine. The recessive allele “p” result in lack of the enzyme and as a consequence phenylketonuria (PKU) can ensure. A woman who was spared the dire effect of PKU as a result of a special diet during infancy and childhood is married to a man who does not have PKU but does carry the recessive allele. During her pregnancy the woman is placed on a special diet once more, since excess phenylalanine and other toxic product can cross the placenta in a PKU women and resulted in mental retardation in the new born. What geneotype are to be expected among the off spring in this case and what would be their phenotype?arrow_forwardExplain why most loss-of-function alleles (hypomorphic or amorphic) are recessive to wild-type alleles, but some are incompletely dominant or dominant.arrow_forwardThe allele of the gene responsible for the lung disorder, cystic fibrosis rose to prominence in Europe in the 1800s. Cystic fibrosis disease results from thick mucus accumulating in the lungs, which occurs in individuals who are homozygous for the CF allele. A pleiotropic effect is that heterozygous individuals are less likely to suffer from diarrhea. During the European cholera epidemics of the 1800s, resistance against diarrhea conferred a survival advantage such that approximately one in every 400 people in some European populations have cystic fibrosis. Fill in the table below with the genotype and allele frequencies for this 1 in 400 occurrence and provide the Hardy-Weinberg principle model you will be using. (Assume that individuals with the cystic fibrosis trait (CF) reproduce normally and that good sanitation means that there is currently no fitness advantage to diarrhea resistance.) phenotype CF DR normal (totals) Genotype cc Cc CC Number of Individuals 1 ______…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Biology Today and Tomorrow without Physiology (Mi...BiologyISBN:9781305117396Author:Cecie Starr, Christine Evers, Lisa StarrPublisher:Cengage LearningHuman Biology (MindTap Course List)BiologyISBN:9781305112100Author:Cecie Starr, Beverly McMillanPublisher:Cengage LearningHuman Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
Biology Today and Tomorrow without Physiology (Mi...
Biology
ISBN:9781305117396
Author:Cecie Starr, Christine Evers, Lisa Starr
Publisher:Cengage Learning
Human Biology (MindTap Course List)
Biology
ISBN:9781305112100
Author:Cecie Starr, Beverly McMillan
Publisher:Cengage Learning
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning