Explanation Given data: The atmospheric pressure on the Venus is 9.0 × 10 6 N/m 2 for which the depth of water, is to be determined. Formula used: Write the expression for the pressure inside the water. P u w = P a t m + ρ w g h . Here, ρ w g h denotes the hydrostatic pressure of water, ρ w denotes the density of water, g denotes the acceleration due to gravity, h denotes the depth of water, P a t m denotes the atmospheric pressure, and P u w denotes the pressure under the water. Explanation: As given, the depth is to be calculated for the pressure by equating the atmospheric pressure of the Venus to the pressure inside the water at certain depth. P u w = P a t m , V E N U S P a t m + ρ w g h = P a t m , V E N U S . Here, P a t m + ρ w g h is the pressure under water. Rearrange the above expression for h . h = P a t m , V E N U S − P a t m ρ w g

2nd Edition

ISBN: 9780134601823

Author: ETKINA, Eugenia, Planinšič, G. (gorazd), Van Heuvelen, Alan

Publisher: Pearson,

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Density of Solids

The density of a substance refers to how much matter is present in a given amount of space. It is expressed as the ratio of the mass of the substance to its volume.

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Chapter 13, Problem 42P

To determine

The depth inside the water from the sea level up to which the pressure becomes equal to 9.0×106 N/m2 and this pressure is the same as that of the atmospheric pressure on the Venus.

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Chapter 13, Problem 41P

Chapter 13, Problem 43P

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The depth inside the water from the sea level up to which the pressure becomes equal to 9.0 × 10 6 N/m 2 and this pressure is the same as that of the atmospheric pressure on the Venus.

Solution Summary: The author calculates the depth of water by equating the atmospheric pressure of the Venus to the pressure inside the water at certain depth.

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The depth inside the water from the sea level up to which the pressure becomes equal to 9.0×106 N/m2 and this pressure is the same as that of the atmospheric pressure on the Venus.

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Chapter 13 Solutions