
(a)
Interpretation: The Lewis dot structure of the atoms has to be found by using their valence electrons present in the outermost shell.
Concept introduction: Lewis dot structures are also called electron dot structures. The diagrams are named after Gilbert N. Lewis, who described them in his 1916 article entitled The Atom and the Molecule.
A nucleus of an atom consists of neutrons and protons. Electrons are from closest to outermost shells around the nucleus. Proton and electron have +1 and -1 charge respectively. Neutron has no charge.
Number of protons is equal to number of electrons in the case of neutral atoms.
The number of electrons present in the outermost shell of an atom that participate in forming
Each group present in the periodic table has specific common valence electrons. Therefore, the position of the atom in the periodic table should be known for drawing the Lewis dot structures.
To find: Draw the Lewis dot structure of a boron atom
(b)
Interpretation: The Lewis dot structure of the atoms has to be found by using their valence electrons present in the outermost shell.
Concept introduction: Lewis dot structures are also called electron dot structures. The diagrams are named after Gilbert N. Lewis, who described them in his 1916 article entitled The Atom and the Molecule.
A nucleus of an atom consists of neutrons and protons. Electrons are from closest to outermost shells around the nucleus. Proton and electron have +1 and -1 charge respectively. Neutron has no charge.
Number of protons is equal to number of electrons in the case of neutral atoms.
The number of electrons present in the outermost shell of an atom that participate in forming chemical bonds with other atoms is called valence electrons.
Each group present in the periodic table has specific common valence electrons. Therefore, the position of the atom in the periodic table should be known for drawing the Lewis dot structures.
To find: Draw the Lewis dot structure of a nitrogen atom

Want to see the full answer?
Check out a sample textbook solution
Chapter 1 Solutions
Organic Chemistry
- Consider the reaction of the cyclopentanone derivative shown below. i) NaOCH2CH3 CH3CH2OH, 25°C ii) CH3!arrow_forwardWhat constitutes a 'reference material', and why does its utilization play a critical role in the chemical analysis of food products? Provide examples.arrow_forwardExplain what calibration is and why it is essential in relation to food analysis. Provide examples.arrow_forward
- The cobalt mu-hydroxide complex cobaltate(III) of potassium is a dinuclear complex. Correct?arrow_forwardThe cobalt mi-hydroxide complex cobaltate(III) of potassium is a dinuclear complex. Correct?arrow_forward3. Arrange the different acids in Exercise B # 2 from the strongest (1) to the weakest acid (10). 1. 2. (strongest) 3. 4. 5. 6. 7. 8. 9. 10 10. (weakest)arrow_forward
- Name Section Score Date EXERCISE B pH, pOH, pка, AND PKD CALCULATIONS 1. Complete the following table. Solution [H+] [OH-] PH РОН Nature of Solution A 2 x 10-8 M B 1 x 10-7 M C D 12.3 6.8 2. The following table contains the names, formulas, ka or pka for some common acids. Fill in the blanks in the table. (17 Points) Acid Name Formula Dissociation reaction Ka pka Phosphoric acid H₂PO₁ H3PO4 H++ H₂PO 7.08 x 10-3 Dihydrogen H₂PO H₂PO H+ HPO 6.31 x 10-6 phosphate Hydrogen HPO₁ 12.4 phosphate Carbonic acid H2CO3 Hydrogen HCO 6.35 10.3 carbonate or bicarbonate Acetic acid CH,COOH 4.76 Lactic acid CH₂CHOH- COOH 1.38 x 10 Ammonium NH 5.63 x 10-10 Phenol CH₂OH 1 x 10-10 Protonated form CH3NH3* 3.16 x 10-11 of methylaminearrow_forwardIndicate whether it is true that Co(III) complexes are very stable.arrow_forwardMnO2 acts as an oxidant in the chlorine synthesis reaction.arrow_forward
- In Potassium mu-dihydroxydicobaltate (III) tetraoxalate K4[Co2(C2O4)4(OH)2], indicate whether the OH ligand type is bidentate.arrow_forwardImagine an electrochemical cell based on these two half reactions with electrolyte concentrations as given below: Oxidation: Pb(s) → Pb2+(aq, 0.10 M) + 2 e– Reduction: MnO4–(aq, 1.50 M) + 4 H+(aq, 2.0 M) + 3 e– → MnO2(s) + 2 H2O(l) Calculate Ecell (assuming temperature is standard 25 °C).arrow_forward: ☐ + Draw the Fischer projection of the most common naturally-occurring form of aspartate, with the acid group at the top and the side chain at the bottom. Important: be sure your structure shows the molecule as it would exist at physiological pH. Click and drag to start drawing a structure. ✓arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





