To draw pictures showing how the guest ( 1,2 ) may bind in the pores of each polymer ( A,B ) and to propose an explanation for differences in binding specificity. Concept introduction: The binding of guest and host may be simply due to hydrogen bonding or by forming a covalent bond also. The binding of guest and host depends upon the groups present in the respective compounds. If the guest and host has only hydrogen acceptors and hydrogen donor groups then the interaction between these two will be due to hydrogen bonding. To draw: To draw pictures depicting the binding of guest (1,2) with polymer (A,B) and to propose an explanation for the binding specificity.

Question

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Answer 1

Question

Chapter 1, Problem 77CP

Interpretation Introduction

Interpretation:

To draw pictures showing how the guest (1,2) may bind in the pores of each polymer (A,B) and to propose an explanation for differences in binding specificity.

Concept introduction:

The binding of guest and host may be simply due to hydrogen bonding or by forming a covalent bond also. The binding of guest and host depends upon the groups present in the respective compounds. If the guest and host has only hydrogen acceptors and hydrogen donor groups then the interaction between these two will be due to hydrogen bonding.

To draw: To draw pictures depicting the binding of guest (1,2) with polymer (A,B) and to propose an explanation for the binding specificity.

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Answer 2

Question

Chapter 1, Problem 77CP

Interpretation Introduction

Interpretation:

To draw pictures showing how the guest (1,2) may bind in the pores of each polymer (A,B) and to propose an explanation for differences in binding specificity.

Concept introduction:

The binding of guest and host may be simply due to hydrogen bonding or by forming a covalent bond also. The binding of guest and host depends upon the groups present in the respective compounds. If the guest and host has only hydrogen acceptors and hydrogen donor groups then the interaction between these two will be due to hydrogen bonding.

To draw: To draw pictures depicting the binding of guest (1,2) with polymer (A,B) and to propose an explanation for the binding specificity.

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Answer 3

Question

Chapter 1, Problem 77CP

Interpretation Introduction

Interpretation:

To draw pictures showing how the guest (1,2) may bind in the pores of each polymer (A,B) and to propose an explanation for differences in binding specificity.

Concept introduction:

The binding of guest and host may be simply due to hydrogen bonding or by forming a covalent bond also. The binding of guest and host depends upon the groups present in the respective compounds. If the guest and host has only hydrogen acceptors and hydrogen donor groups then the interaction between these two will be due to hydrogen bonding.

To draw: To draw pictures depicting the binding of guest (1,2) with polymer (A,B) and to propose an explanation for the binding specificity.

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Answer 4

Question

Chapter 1, Problem 77CP

Interpretation Introduction

Interpretation:

To draw pictures showing how the guest (1,2) may bind in the pores of each polymer (A,B) and to propose an explanation for differences in binding specificity.

Concept introduction:

The binding of guest and host may be simply due to hydrogen bonding or by forming a covalent bond also. The binding of guest and host depends upon the groups present in the respective compounds. If the guest and host has only hydrogen acceptors and hydrogen donor groups then the interaction between these two will be due to hydrogen bonding.

To draw: To draw pictures depicting the binding of guest (1,2) with polymer (A,B) and to propose an explanation for the binding specificity.

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Answer 5

Chapter 1, Problem 77CP

Interpretation Introduction

Interpretation:

To draw pictures showing how the guest (1,2) may bind in the pores of each polymer (A,B) and to propose an explanation for differences in binding specificity.

Concept introduction:

The binding of guest and host may be simply due to hydrogen bonding or by forming a covalent bond also. The binding of guest and host depends upon the groups present in the respective compounds. If the guest and host has only hydrogen acceptors and hydrogen donor groups then the interaction between these two will be due to hydrogen bonding.

To draw: To draw pictures depicting the binding of guest (1,2) with polymer (A,B) and to propose an explanation for the binding specificity.

Answer 6

Chapter 1, Problem 77CP

Interpretation Introduction

Interpretation:

To draw pictures showing how the guest (1,2) may bind in the pores of each polymer (A,B) and to propose an explanation for differences in binding specificity.

Concept introduction:

The binding of guest and host may be simply due to hydrogen bonding or by forming a covalent bond also. The binding of guest and host depends upon the groups present in the respective compounds. If the guest and host has only hydrogen acceptors and hydrogen donor groups then the interaction between these two will be due to hydrogen bonding.

To draw: To draw pictures depicting the binding of guest (1,2) with polymer (A,B) and to propose an explanation for the binding specificity.

Answer 7

Chapter 1, Problem 77CP

Interpretation Introduction

Interpretation:

To draw pictures showing how the guest (1,2) may bind in the pores of each polymer (A,B) and to propose an explanation for differences in binding specificity.

Concept introduction:

The binding of guest and host may be simply due to hydrogen bonding or by forming a covalent bond also. The binding of guest and host depends upon the groups present in the respective compounds. If the guest and host has only hydrogen acceptors and hydrogen donor groups then the interaction between these two will be due to hydrogen bonding.

To draw: To draw pictures depicting the binding of guest (1,2) with polymer (A,B) and to propose an explanation for the binding specificity.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 1.2 - Prob. 1LTS Ch. 1.2 - Prob. 1PTS Ch. 1.2 - Prob. 2ATS Ch. 1.2 - Prob. 3ATS Ch. 1.2 - Prob. 4ATS Ch. 1.3 - Prob. 2LTS Ch. 1.3 - Prob. 5PTS Ch. 1.3 - Prob. 6ATS Ch. 1.3 - Prob. 7ATS Ch. 1.3 - Prob. 8ATS

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Chapter 1 Solutions