Finite Mathematics for Business, Economics, Life Sciences and Social Sciences
14th Edition
ISBN: 9780134677972
Author: Barnett
Publisher: PEARSON
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Textbook Question
Chapter 1.3, Problem 17E
Freezing temperature. Ethylene glycol and propylene glycol are liquids used in antifreeze and deicing solutions. Ethylene glycol is listed as a hazardous chemical by the Environmental Protection Agency, while propylene glycol is generally regarded as safe. Table 11 lists the freezing temperature for various concentrations (as a percentage of total weight) of each chemical in a solution used to deice airplanes. A linear regression model for the ethylene glycol data in Table 11 is
where
(A) Draw a
(B) Use the model to estimate the freezing temperature to the nearest degree of a solution that
is 30% ethylene glycol.
(C) Use the model to estimate the percentage of ethylene glycol in a solution that freezes at
15°F.
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Question 1:
If a barometer were built using oil (p = 0.92 g/cm³) instead of mercury (p =
13.6 g/cm³), would the column of oil be higher than, lower than, or the same as the
column of mercury at 1.00 atm? If the level is different, by what factor? Explain. (5 pts)
Solution:
A barometer works based on the principle that the pressure exerted by the liquid column
balances atmospheric pressure. The pressure is given by:
P = pgh
Since the atmospheric pressure remains constant (P = 1.00 atm), the height of the
liquid column is inversely proportional to its density:
Step 1: Given Data
PHg
hol=hgx
Poil
• Density of mercury: PHg = 13.6 g/cm³
Density of oil: Poil = 0.92 g/cm³
• Standard height of mercury at 1.00 atm: hμg
Step 2: Compute Height of Oil
= 760 mm = 0.760 m
13.6
hoil
= 0.760 x
0.92
hoil
= 0.760 × 14.78
hoil
= 11.23 m
Step 3: Compare Heights
Since oil is less dense than mercury, the column of oil must be much taller than that of
mercury. The factor by which it is taller is:
Final…
Question 3:
A sealed flask at room temperature contains a mixture of neon (Ne) and nitrogen (N2)
gases.
Ne has a mass of 3.25 g and exerts a pressure of 48.2 torr.
.
N2 contributes a pressure of 142 torr.
• What is the mass of the N2 in the flask?
• Atomic mass of Ne = 20.1797 g/mol
• Atomic mass of N = 14.0067 g/mol
Solution:
We will use the Ideal Gas Law to determine the number of moles of each gas and
calculate the mass of N2.
PV = nRT
where:
• P = total pressure
•
V volume of the flask (same for both gases)
n = number of moles of gas
•
R 0.0821 L atm/mol K
• T = Room temperature (assume 298 K)
Since both gases are in the same flask, their partial pressures correspond to their mole
fractions.
Step 1: Convert Pressures to Atmospheres
48.2
PNe
= 0.0634 atm
760
142
PN2
=
= 0.1868 atm
760
Step 2: Determine Moles of Ne
nNe =
mass
molar mass
3.25
nNe
20.1797
nne 0.1611 mol
Step 3: Use Partial Pressure Ratio to Find n
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Chapter 1 Solutions
Finite Mathematics for Business, Economics, Life Sciences and Social Sciences
Ch. 1.1 - According to equality property 2, multiplying both...Ch. 1.1 - Replace ? with < or > in each of the following:...Ch. 1.1 - The solution to Example 5B shows the graph of the...Ch. 1.1 - Solve and check: 3x2(2x5)=2(x+3)8Ch. 1.1 - Solve and check: x+13x4=12Ch. 1.1 - Matched Problem 3 If a cardboard box has length L,...Ch. 1.1 - Replace each question mark with either < or >....Ch. 1.1 - (A) Write 7,4 as a double inequality and graph....Ch. 1.1 - Solve and graph: 3(x1)5(x+2)5Ch. 1.1 - Solve and graph: 83x57
Ch. 1.1 - Mary paid 8.5 sales tax and a 190 title and...Ch. 1.1 - How many bike computers would a company have to...Ch. 1.1 - What net annual salary in 1973 would have had the...Ch. 1.1 - In Problems 1-6, solve for x. 5x+3=x+23Ch. 1.1 - In Problems 1-6, solve for x. 7x6=5x24Ch. 1.1 - In Problems 1-6, solve for x. 9(4x)=2(x+7)Ch. 1.1 - In Problems 1-6, solve for x. 3(x+6)=52(x+1)Ch. 1.1 - In Problems 1-6, solve for x. x+14=x2+5Ch. 1.1 - In Problems 1-6, solve for x. 2x+135x2=4Ch. 1.1 - In Problems 7-12, write the interval as an...Ch. 1.1 - In Problems 7-12, write the interval as an...Ch. 1.1 - In Problems 7-12, write the interval as an...Ch. 1.1 - In Problems 7-12, write the interval as an...Ch. 1.1 - In Problems 7-12, write the interval as an...Ch. 1.1 - In Problems 7-12, write the interval as an...Ch. 1.1 - In Problems 13-18, write the solution set using...Ch. 1.1 - In Problems 13-18, write the solution set using...Ch. 1.1 - In Problems 13-18, write the solution set using...Ch. 1.1 - In Problems 13-18, write the solution set using...Ch. 1.1 - In Problems 13-18, write the solution set using...Ch. 1.1 - In Problems 13-18, write the solution set using...Ch. 1.1 - In Problems 19-32, find the solution set. x4+12=18Ch. 1.1 - In Problems 19-32, find the solution set. m34=23Ch. 1.1 - In Problems 19-32, find the solution set. y532Ch. 1.1 - In Problems 19-32, find the solution set. x456Ch. 1.1 - In Problems 19-32, find the solution set....Ch. 1.1 - In Problems 19-32, find the solution set....Ch. 1.1 - In Problems 19-32, find the solution set....Ch. 1.1 - In Problems 19-32, find the solution set. 34x=5x+1Ch. 1.1 - In Problems 19-32, find the solution set. 3y4y3Ch. 1.1 - In Problems 19-32, find the solution set. x22x5Ch. 1.1 - In Problems 19-32, find the solution set. x5x6=65Ch. 1.1 - In Problems 19-32, find the solution set. y4y3=12Ch. 1.1 - In Problems 19-32, find the solution set. m5335m2Ch. 1.1 - In Problems 19-32, find the solution set. u223u3+2Ch. 1.1 - In Problems 33-36, solve and graph. 23x714Ch. 1.1 - In Problems 33-36, solve and graph. 45x+621Ch. 1.1 - In Problems 33-36, solve and graph. 495C+3268Ch. 1.1 - In Problems 33-36, solve and graph. 123t+511Ch. 1.1 - In Problems 37-42, solve for the indicated...Ch. 1.1 - In Problems 37-42, solve for the indicated...Ch. 1.1 - In Problems 37-42, solve for the indicated...Ch. 1.1 - In Problems 37-42, solve for the indicated...Ch. 1.1 - In Problems 37-42, solve for the indicated...Ch. 1.1 - In Problems 37-42, solve for the indicated...Ch. 1.1 - In Problems 43 and 44, solve and graph. 347x18Ch. 1.1 - In Problems 43 and 44, solve and graph. 1083u6Ch. 1.1 - If both a and b are positive numbers and b/a. is...Ch. 1.1 - If both a and b are negative numbers and b/a is...Ch. 1.1 - Ticket sales. 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