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Concept explainers
(a)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
(b)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
(c)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
(d)
Interpretation:
For the given molecule, whether cis‑trans isomerism is possible has to be indicated.
Concept Introduction:
Alkenes are hydrocarbons that contain at least one double bond in it. There will not be any free rotation of the double bond in alkene. Hence, cis‑trans isomerism is possible. The first and foremost condition for the alkene to exhibit cis‑trans isomerism is that the carbon attached in either end of double bond must have different groups attached to it.
A cis isomer is the one in which the same groups are present on same side of both the carbon atoms present in the double bond.
A trans isomer is the one in which the same groups are present on opposite side of both the carbon atoms present in the double bond.
Cis‑trans isomerism is not possible if any one of the carbon atom bonded to the double bond bears two identical groups.
Cis‑trans isomers are not constitutional isomers but they are stereoisomers.
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Chapter 13 Solutions
Study Guide with Selected Solutions for Stoker's General, Organic, and Biological Chemistry, 7th
- I don't understand what to put for final step. Does that just mean termination? And would a radical form when I add bromine to ch2 between the rings?arrow_forwardNonearrow_forward11 1 Which one of the following compounds would show a proton NMR signal at the highest chemical shift? (7pts) cl @amitabh CI CI d) Cl CICIarrow_forward
- Nonearrow_forwardH2SO4 (cat.), H₂O 100 °C NH₂arrow_forwardX Draw the major products of the elimination reaction below. If elimination would not occur at a significant rate, check the box under the drawing area instead. ది www. Cl + OH Elimination will not occur at a significant rate. Click and drag to start drawing a structure.arrow_forward
- Nonearrow_forward1A H 2A Li Be Use the References to access important values if needed for this question. 8A 3A 4A 5A 6A 7A He B C N O F Ne Na Mg 3B 4B 5B 6B 7B 8B-1B 2B Al Si P 1B 2B Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe * Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn Fr Ra Ac Rf Ha ****** Ce Pr Nd Pm Sm Eu Gd Tb Dy Ho Er Tm Yb Lu Th Pa U Np Pu Am Cm Bk Cf Es Fm Md No Lr Analyze the following reaction by looking at the electron configurations given below each box. Put a number and a symbol in each box to show the number and kind of the corresponding atom or ion. Use the smallest integers possible. cation anion + + Shell 1: 2 Shell 2: 8 Shell 3: 1 Shell 1 : 2 Shell 2 : 6 Shell 1 : 2 Shell 2: 8 Shell 1: 2 Shell 2: 8arrow_forwardNonearrow_forward
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