
Concept explainers
(a)
Interpretation:
The spatial arrangement for the
Concept Introduction:
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and
Saturated hydrocarbons are
Alkane has general molecular formula as
Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry. The carbon atoms that have only single bonds attached to it will have tetrahedral geometry. The carbon atoms that have a triple bond attached to it will have a linear geometry.
(a)

Answer to Problem 13.37EP
The spatial arrangement is identified as tetrahedral.
Explanation of Solution
Given structure is,
Looking into the left most carbon atom present in the given structure, it is not bonded to any double bonds or triple bond. This carbon atom has only four single bonds (three with hydrogen and one with carbon atom). Therefore, the spatial arrangement of the left-most carbon atom is tetrahedral.
The spatial arrangement of the left-most carbon atom is identified.
(b)
Interpretation:
The spatial arrangement for the chemical bonds in the left‑most carbon atom in the given structure has to be identified.
Concept Introduction:
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Saturated hydrocarbons are alkanes. Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.
Alkane has general molecular formula as
Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry. The carbon atoms that have only single bonds attached to it will have tetrahedral geometry. The carbon atoms that have a triple bond attached to it will have a linear geometry.
(b)

Answer to Problem 13.37EP
The spatial arrangement is identified as tetrahedral.
Explanation of Solution
Given structure is,
Looking into the left most carbon atom present in the given structure, it is not bonded to any double bonds or triple bond. This carbon atom has only four single bonds (three with hydrogen and one with carbon atom). Therefore, the spatial arrangement of the left-most carbon atom is tetrahedral.
The spatial arrangement of the left-most carbon atom is identified.
(c)
Interpretation:
The spatial arrangement for the chemical bonds in the left‑most carbon atom in the given structure has to be identified.
Concept Introduction:
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Saturated hydrocarbons are alkanes. Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.
Alkane has general molecular formula as
Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry. The carbon atoms that have only single bonds attached to it will have tetrahedral geometry. The carbon atoms that have a triple bond attached to it will have a linear geometry.
(c)

Answer to Problem 13.37EP
The spatial arrangement is identified as trigonal planar.
Explanation of Solution
Given structure is,
Looking into the left most carbon atom present in the given structure, it is bonded to one double bond. This carbon atom has only two single bonds with hydrogen and a double bond with carbon atom. Therefore, the spatial arrangement of the left-most carbon atom is trigonal planar.
The spatial arrangement of the left-most carbon atom is identified.
(d)
Interpretation:
The spatial arrangement for the chemical bonds in the left‑most carbon atom in the given structure has to be identified.
Concept Introduction:
Hydrocarbons are the organic compounds that contain only hydrogen and carbon atoms. Hydrocarbon derivatives are the one in which the compounds contain hydrogen and carbon atoms along with one or more additional elements. The additional elements that can be present in hydrocarbon derivatives are oxygen, nitrogen, sulphur, chlorine, bromine etc.
Hydrocarbons are further classified into two categories. They are saturated hydrocarbons and unsaturated hydrocarbons. The hydrocarbons that contain single bonds between carbon atoms in the entire molecule is known as saturated hydrocarbon. The hydrocarbons that contain atleast one double or triple bond between two carbon atoms in the entire molecule is known as unsaturated hydrocarbon.
Saturated hydrocarbons are alkanes. Unsaturated hydrocarbons are alkene, alkyne and aromatic hydrocarbons.
Alkane has general molecular formula as
Considering the geometry of carbon atoms, the carbon atoms that have double bonds will have trigonal planar geometry. The carbon atoms that have only single bonds attached to it will have tetrahedral geometry. The carbon atoms that have a triple bond attached to it will have a linear geometry.
(d)

Answer to Problem 13.37EP
The spatial arrangement is identified as tetrahedral.
Explanation of Solution
Given structure is,
Looking into the left most carbon atom present in the given structure, it is not bonded to any double bonds or triple bond. This carbon atom has only four single bonds (three with hydrogen and one with carbon atom). Therefore, the spatial arrangement of the left-most carbon atom is tetrahedral.
The spatial arrangement of the left-most carbon atom is identified.
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Chapter 13 Solutions
Study Guide with Selected Solutions for Stoker's General, Organic, and Biological Chemistry, 7th
- For each reaction below, decide if the first stable organic product that forms in solution will create a new CC bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. དྲ。 ✗MgBr ? O CI Will the first product that forms in this reaction create a new C-C bond? Yes No • ? Will the first product that forms in this reaction create a new CC bond? Yes No × : ☐ Xarrow_forwardPredict the major products of this organic reaction: OH NaBH4 H ? CH3OH Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. ☐ : Sarrow_forwardPredict the major products of this organic reaction: 1. LIAIHA 2. H₂O ? Note: be sure you use dash and wedge bonds when necessary, for example to distinguish between major products with different stereochemistry. Click and drag to start drawing a structure. X : ☐arrow_forward
- For each reaction below, decide if the first stable organic product that forms in solution will create a new C - C bond, and check the appropriate box. Next, for each reaction to which you answered "Yes" to in the table, draw this product in the drawing area below. Note for advanced students: for this problem, don't worry if you think this product will continue to react under the current conditions - just focus on the first stable product you expect to form in solution. NH2 tu ? ? OH Will the first product that forms in this reaction create a new CC bond? Yes No Will the first product that forms in this reaction create a new CC bond? Yes No C $ ©arrow_forwardAs the lead product manager at OrganometALEKS Industries, you are trying to decide if the following reaction will make a molecule with a new C-C bond as its major product: 1. MgCl ? 2. H₂O* If this reaction will work, draw the major organic product or products you would expect in the drawing area below. If there's more than one major product, you can draw them in any arrangement you like. Be sure you use wedge and dash bonds if necessary, for example to distinguish between major products with different stereochemistry. If the major products of this reaction won't have a new CC bond, just check the box under the drawing area and leave it blank. Click and drag to start drawing a structure. This reaction will not make a product with a new CC bond. G marrow_forwardIncluding activity coefficients, find [Hg22+] in saturated Hg2Br2 in 0.00100 M NH4 Ksp Hg2Br2 = 5.6×10-23.arrow_forward
- give example for the following(by equation) a. Converting a water insoluble compound to a soluble one. b. Diazotization reaction form diazonium salt c. coupling reaction of a diazonium salt d. indacator properties of MO e. Diazotization ( diazonium salt of bromobenzene)arrow_forward2-Propanone and ethyllithium are mixed and subsequently acid hydrolyzed. Draw and name the structures of the products.arrow_forward(Methanesulfinyl)methane is reacted with NaH, and then with acetophenone. Draw and name the structures of the products.arrow_forward
- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
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