Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card
5th Edition
ISBN: 9781260170405
Author: SMITH
Publisher: MCG
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Chapter 13, Problem 13.50P
A chiral compound
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Chapter 13 Solutions
Package: Loose Leaf for Organic Chemistry with Biological Topics with Connect Access Card
Ch. 13 - What is the mass of the molecular ion formed from...Ch. 13 - Prob. 13.2PCh. 13 - Use the following information to propose a...Ch. 13 - Prob. 13.4PCh. 13 - What molecular ions would you expect for the...Ch. 13 - The mass spectrum of 2,3-dimethylpentane also...Ch. 13 - The base peak in the mass spectrum of 2, 2,...Ch. 13 - (a) What mass spectral fragments are formed by ...Ch. 13 - What cations are formed in the mass spectrometer...Ch. 13 - The low-resolution mass spectrum of an unknown...
Ch. 13 - Benzene, toluene, and p-xylene BTX are often added...Ch. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - Prob. 13.15PCh. 13 - How do the IR spectra of the isomers cyclopentane...Ch. 13 - Problem 13.17 How do the three isomers of...Ch. 13 - Problem 13.18 What functional groups are...Ch. 13 - Problem-13.19 What are the major IR absorptions in...Ch. 13 - Problem-13.20 What are the major IR absorptions in...Ch. 13 - Problem-13.21 Which of the following possible...Ch. 13 - Problem-13.22 Propose structures consistent with...Ch. 13 - 13.23 What major IR absorptions are present above ...Ch. 13 - Problem-13.24 The mass spectrum of the following...Ch. 13 - Prob. 13.25PCh. 13 - Which compound gives a molecular ion at m/z= 122,...Ch. 13 - Propose two molecular formulas for each molecular...Ch. 13 - Propose four possible structures for a hydrocarbon...Ch. 13 - Problem-13.29 What is the molecular formula for...Ch. 13 - Problem-13.30 Propose a molecular formula for rose...Ch. 13 - 13.31 Match each structure to its mass spectrum
Ch. 13 - 13.32 Propose two possible structures for a...Ch. 13 - 13.33 What cations are formed in the mass...Ch. 13 - 13.34 and have the same molecular ion in the...Ch. 13 - 13.35 For each compound, assign likely...Ch. 13 - Prob. 13.36PCh. 13 - 13.37 Propose a structure consistent with each...Ch. 13 - 13.38 A low-resolution mass spectrum of the...Ch. 13 - 13.39 Primary alcohols often show a peak in their...Ch. 13 - 13.40 Like alcohols, ethers undergo α cleavage by...Ch. 13 - 13.41 Which of the highlighted bonds absorbs at...Ch. 13 - 13.42 What major IR absorptions are present above ...Ch. 13 - 13.43 How would each of the following pairs of...Ch. 13 - 13.44 Morphine, heroin, and oxycodone are three...Ch. 13 - 13.45 Reduction of cyclohex-2-enone can yield...Ch. 13 - Prob. 13.46PCh. 13 - 13.47 Match each compound to its IR spectrum
Ch. 13 - 13.48 Propose possible structures consistent with...Ch. 13 - A chiral hydrocarbon X exhibits a molecular ion at...Ch. 13 - 13.50 A chiral compound has a strong absorption...Ch. 13 - 13.51 Treatment of benzoic acid with followed by...Ch. 13 - 13.52 Treatment of benzaldehyde with in aqueous ...Ch. 13 - Prob. 13.53PCh. 13 - 13.54 Reaction of 2-methylpropanoic acid with ...Ch. 13 - 13.55 Reaction of pentanoyl chloride with lithium...Ch. 13 - Prob. 13.56PCh. 13 - 13.57 Treatment of anisole with and forms P,...Ch. 13 - 13.58 Reaction of with forms compound ,...Ch. 13 - Problem-13.59 The carbonyl absorption of an amide...Ch. 13 - Prob. 13.60PCh. 13 - Problem-13.61 Explain why a ketone carbonyl...Ch. 13 - 13.62 Oxidation of citronellol, a constituent of...
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- A molecule of the molecular formula C5H11Br gives rise to the NMR spectrum below. When reacted with NaOH and water, it forms a product which by NMR has 2 protons 1H at 5.4 ppm and 1H at 5.5 ppm each having a 3J coupling of 17 Hz. (other protons also present) The product also has an IR stretch at 1550 cm 1. Provide the structures of the starting material and product. NaOH H,0 C;H„Br 6H triplet 4H quintet 1H quintet 10 8 Ppmarrow_forwardAn organic compound B with formula C6H14O has the following: IR Spectroscopy 2974 cm-1, 1080 cm-1 Mass Spectrometry 102 (M+), 87, 73 1H NMR Spectroscopy Eight signals at δ 1.10 (d, 3H), 1.13 (dd, 3H), 1.14 (dd, 3H), 1.59 (ddq, 1H), 1.60 (ddq, 1H), 3.19 (ddq, 1H), 3.51 (dq, 1H), 3.50 (dq, 1H). Compound B is obtained by the reaction of compound A with NaH followed by CH3CH2Br. The stereochemistry of A is "S" Using this information, deduce a plausible structure for Compound A with correct stereochemistry.arrow_forwardDeduce the structure of compound C.arrow_forward
- As reaction of (CH3)2CO with LIC≡CH followed by H2O affords compound D, which has a molecular ion in its mass spectrum at 84 and prominent absorptions in its IR spectrum at 3600−3200, 3303, 2938, and 2120 cm−1. D shows the following 1H NMR spectral data: 1.53 (singlet, 6 H), 2.37 (singlet, 1 H), and 2.43 (singlet, 1 H) ppm. What is the structure of D?arrow_forwardProvide a structure for the compound with molecular formula C5H10O and with the following spectroscopic data.IR: 1720 cm−11H NMR: 0.9δ (triplet, I=3H), 1.7δ (sextet, I=2H), 2.1δ (singlet, I=3H), 2.4δ (triplet, I=2H)arrow_forwardIdentify the structures of isomers H and I (molecular formula C8H11N).a.Compound H: IR absorptions at 3365, 3284, 3026, 2932, 1603, and 1497 cm−1b.Compound I: IR absorptions at 3367, 3286, 3027, 2962, 1604, and 1492 cm−1arrow_forward
- A chiral compound Y has a strong absorption at 2970−2840 cm−1 in its IR spectrum and gives the following mass spectrum. Propose a structure for Y.arrow_forwardA hydrocarbon, compound B, has molecular formula C6H6, and gave an NMR spectrum with two signals: delta 6.55 pm and delta 3.84 pm with peak ratio of 2:1. When warmed in pyridine for three hr, compound B quantitatively converts to benzene. Mild hydrogenation of B yielded another compound C with mass spectrum of m/z 82. Infrared spectrum showed no double bonds; NMR spectrum showed one broad peak at delta 2.34 ppm. With this information, address the following questions. a) How many rings are in compound C? b) How many rings are probably in B? How many double bonds are in B? c) Can you suggest a structure for compounds B and C? d) In the NMR spectrum of B, the up-field signal was a quintet, and the down field signal was a triplet. How must you account for these splitting patterns?arrow_forwardTreatment of 2-methylpropanenitrile [(CH3)2CHCN] with CH3CH2CH2MgBr, followed by aqueous acid, affords compound V, which has molecular formula C7H14O. V has a strong absorption in its IR spectrum at 1713 cm−1, and gives the following 1H NMR data: 0.91 (triplet, 3 H), 1.09 (doublet, 6 H), 1.6 (multiplet, 2 H), 2.43 (triplet, 2 H), and 2.60 (septet, 1 H) ppm. What is the structure of V? We will learn about this reaction in Chapter 20.arrow_forward
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