Treatment of benzoic acid ( C 6 H 5 COOH ) with NaOH followed by 1 -iodo- 3 -methylbutane forms H . H has a molecular ion at 192 and IR absorptions at 3064, 3035, 2960 - 2872 and 1721 cm − 1 . Propose a structure for H .
Treatment of benzoic acid ( C 6 H 5 COOH ) with NaOH followed by 1 -iodo- 3 -methylbutane forms H . H has a molecular ion at 192 and IR absorptions at 3064, 3035, 2960 - 2872 and 1721 cm − 1 . Propose a structure for H .
Solution Summary: The author explains that the molecular ion is the radical cation formed by the ejection of electrons from a molecule.
Treatment of benzoic acid
(
C
6
H
5
COOH
)
with
NaOH
followed by
1
-iodo-
3
-methylbutane forms
H
.
H
has a molecular ion at
192
and IR absorptions at
3064, 3035, 2960
-
2872
and
1721 cm
−
1
. Propose a structure for
H
.
bre
The reaction sequence shown in Scheme 5 demonstrates the synthesis of a
substituted benzene derivative Q.
wolsd works 2
NH2
NaNO2, HCI
(apexe) 13× (1
HNO3, H2SO4
C6H5CIN2
0°C
HOTE
CHINO₂
N
O
*O₂H (
PO
Q
Я
Scheme 5
2 bag abouoqmics to sounde odi WEIC
(i)
Draw the structure of intermediate O.
[2 marks]
to noitsmot od: tot meinedogm, noit so oft listsb ni zaupaib bas wa
(ii) Draw the mechanism for the transformation of aniline N to intermediate O.
Spoilage
(b)
[6 marks]
(iii) Identify the reagent X used to convert compound O to the iodinated compound
[tom E
P.
vueimado oilovonsa ni moitos nolisbnolov ayd toes ai tedw nisiqx
(iv) Identify the possible structures of compound Q.
[2 marks]
[2 marks]
[shom 2]
(v)
bus noires goiribbeolovo xnivollot adj to subora sidab
Draw the mechanism for the transformation of intermediate P to compound Q.
[5 marks]
vi
(vi) Account for the regiochemical outcome observed in the reaction forming
compound Q.
[3 marks]
PROBLEM 4 Solved
Show how 1-butanol can be converted into the following compounds:
a.
PROBLEM 5+
b.
d.
-C=
N
Which alkene is the major product of this dehydration?
OH
H2SO4
heat
Chapter 13 Solutions
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