(a) Interpretation: The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory. Concept introduction: The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions. The structures on the left side of the reaction arrow ( ) are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on the right side of the reaction arrow ( ) are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Question

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Answer 1

Question

Chapter 13, Problem 13.28P

Interpretation Introduction

(a)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on the right side of the reaction arrow

() are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 7

In the given synthetic route, the reactant having functional group epoxide is converted to an alcohol named which is further converted to an alkene named on reaction with appropriate reagents as mentioned. In the first step, the first reagent used is phenylmagnesium bromide in the solvent diethyl ether, and the second reagent is which represents the aqueous acidic condition. In the second step, the reagent is phosphoric acid and is the reaction temperature. Thus, the word form of the above synthetic scheme can be written as follows:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Conclusion

The given synthesis scheme is converted to word form by identifying the names of reactants, reagents, and products.

Interpretation Introduction

(b)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to products by reacting with the reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane, to produce phenylpropanone. Then, add the molecular bromine in the presence of acetic acid to form which further reacts with sodium acetate to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 19

The given synthetic route is of three steps. In the first step, the reactant having functional group ketone named phenylehtanone is converted to another ketone named phenylpropanone. In the second step, phenylpropanone is converted to alpha bromo ketone named , which, in the third step, is further converted to the final product having the ester functional group. In the first step, the first reagent used is lithium diisopropylamide, and the second reagent is iodomethane. In the second step, the reagent is molecular bromine in acetic acid. The reagent for the third step is sodium acetate. Thus, the word form of the above synthetic scheme can be written as follows:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane to produce phenylpropanone. Add the molecular bromine in presence of acetic acid to phenylpropanone to form which further reacts with sodium acetate to yield THE final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

Interpretation Introduction

(c)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants, and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Heat in aqueous hydrochloric acid to form , add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 29

The given synthetic route is of three steps. The nitro functional group remains as it is throughout the reaction sequence, and so, is not considered. In the first step, ether functional group is converted to an alcohol. In the second step, group of alcohol is replaced by bromine, which in the third step is replaced by . In the first step, the reagent used is that represents acidic condition where is the symbol used for heat. In the second step, the reagent is , phosphorous tribromide, and in the third step, the reagent used is sodium azide, . Thus, the word form of the above synthetic scheme can be written as follows:

Heat in aqueous hydrochloric acid to form , and add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

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Answer 2

Question

Chapter 13, Problem 13.28P

Interpretation Introduction

(a)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on the right side of the reaction arrow

() are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 7

In the given synthetic route, the reactant having functional group epoxide is converted to an alcohol named which is further converted to an alkene named on reaction with appropriate reagents as mentioned. In the first step, the first reagent used is phenylmagnesium bromide in the solvent diethyl ether, and the second reagent is which represents the aqueous acidic condition. In the second step, the reagent is phosphoric acid and is the reaction temperature. Thus, the word form of the above synthetic scheme can be written as follows:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Conclusion

The given synthesis scheme is converted to word form by identifying the names of reactants, reagents, and products.

Interpretation Introduction

(b)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to products by reacting with the reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane, to produce phenylpropanone. Then, add the molecular bromine in the presence of acetic acid to form which further reacts with sodium acetate to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 19

The given synthetic route is of three steps. In the first step, the reactant having functional group ketone named phenylehtanone is converted to another ketone named phenylpropanone. In the second step, phenylpropanone is converted to alpha bromo ketone named , which, in the third step, is further converted to the final product having the ester functional group. In the first step, the first reagent used is lithium diisopropylamide, and the second reagent is iodomethane. In the second step, the reagent is molecular bromine in acetic acid. The reagent for the third step is sodium acetate. Thus, the word form of the above synthetic scheme can be written as follows:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane to produce phenylpropanone. Add the molecular bromine in presence of acetic acid to phenylpropanone to form which further reacts with sodium acetate to yield THE final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

Interpretation Introduction

(c)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants, and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Heat in aqueous hydrochloric acid to form , add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 29

The given synthetic route is of three steps. The nitro functional group remains as it is throughout the reaction sequence, and so, is not considered. In the first step, ether functional group is converted to an alcohol. In the second step, group of alcohol is replaced by bromine, which in the third step is replaced by . In the first step, the reagent used is that represents acidic condition where is the symbol used for heat. In the second step, the reagent is , phosphorous tribromide, and in the third step, the reagent used is sodium azide, . Thus, the word form of the above synthetic scheme can be written as follows:

Heat in aqueous hydrochloric acid to form , and add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

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Answer 3

Question

Chapter 13, Problem 13.28P

Interpretation Introduction

(a)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on the right side of the reaction arrow

() are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 7

In the given synthetic route, the reactant having functional group epoxide is converted to an alcohol named which is further converted to an alkene named on reaction with appropriate reagents as mentioned. In the first step, the first reagent used is phenylmagnesium bromide in the solvent diethyl ether, and the second reagent is which represents the aqueous acidic condition. In the second step, the reagent is phosphoric acid and is the reaction temperature. Thus, the word form of the above synthetic scheme can be written as follows:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Conclusion

The given synthesis scheme is converted to word form by identifying the names of reactants, reagents, and products.

Interpretation Introduction

(b)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to products by reacting with the reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane, to produce phenylpropanone. Then, add the molecular bromine in the presence of acetic acid to form which further reacts with sodium acetate to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 19

The given synthetic route is of three steps. In the first step, the reactant having functional group ketone named phenylehtanone is converted to another ketone named phenylpropanone. In the second step, phenylpropanone is converted to alpha bromo ketone named , which, in the third step, is further converted to the final product having the ester functional group. In the first step, the first reagent used is lithium diisopropylamide, and the second reagent is iodomethane. In the second step, the reagent is molecular bromine in acetic acid. The reagent for the third step is sodium acetate. Thus, the word form of the above synthetic scheme can be written as follows:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane to produce phenylpropanone. Add the molecular bromine in presence of acetic acid to phenylpropanone to form which further reacts with sodium acetate to yield THE final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

Interpretation Introduction

(c)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants, and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Heat in aqueous hydrochloric acid to form , add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 29

The given synthetic route is of three steps. The nitro functional group remains as it is throughout the reaction sequence, and so, is not considered. In the first step, ether functional group is converted to an alcohol. In the second step, group of alcohol is replaced by bromine, which in the third step is replaced by . In the first step, the reagent used is that represents acidic condition where is the symbol used for heat. In the second step, the reagent is , phosphorous tribromide, and in the third step, the reagent used is sodium azide, . Thus, the word form of the above synthetic scheme can be written as follows:

Heat in aqueous hydrochloric acid to form , and add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 13, Problem 13.28P

Interpretation Introduction

(a)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on the right side of the reaction arrow

() are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 7

In the given synthetic route, the reactant having functional group epoxide is converted to an alcohol named which is further converted to an alkene named on reaction with appropriate reagents as mentioned. In the first step, the first reagent used is phenylmagnesium bromide in the solvent diethyl ether, and the second reagent is which represents the aqueous acidic condition. In the second step, the reagent is phosphoric acid and is the reaction temperature. Thus, the word form of the above synthetic scheme can be written as follows:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Conclusion

The given synthesis scheme is converted to word form by identifying the names of reactants, reagents, and products.

Interpretation Introduction

(b)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to products by reacting with the reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane, to produce phenylpropanone. Then, add the molecular bromine in the presence of acetic acid to form which further reacts with sodium acetate to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 19

The given synthetic route is of three steps. In the first step, the reactant having functional group ketone named phenylehtanone is converted to another ketone named phenylpropanone. In the second step, phenylpropanone is converted to alpha bromo ketone named , which, in the third step, is further converted to the final product having the ester functional group. In the first step, the first reagent used is lithium diisopropylamide, and the second reagent is iodomethane. In the second step, the reagent is molecular bromine in acetic acid. The reagent for the third step is sodium acetate. Thus, the word form of the above synthetic scheme can be written as follows:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane to produce phenylpropanone. Add the molecular bromine in presence of acetic acid to phenylpropanone to form which further reacts with sodium acetate to yield THE final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

Interpretation Introduction

(c)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants, and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Heat in aqueous hydrochloric acid to form , add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 29

The given synthetic route is of three steps. The nitro functional group remains as it is throughout the reaction sequence, and so, is not considered. In the first step, ether functional group is converted to an alcohol. In the second step, group of alcohol is replaced by bromine, which in the third step is replaced by . In the first step, the reagent used is that represents acidic condition where is the symbol used for heat. In the second step, the reagent is , phosphorous tribromide, and in the third step, the reagent used is sodium azide, . Thus, the word form of the above synthetic scheme can be written as follows:

Heat in aqueous hydrochloric acid to form , and add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 13, Problem 13.28P

Interpretation Introduction

(a)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on the right side of the reaction arrow

() are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 7

In the given synthetic route, the reactant having functional group epoxide is converted to an alcohol named which is further converted to an alkene named on reaction with appropriate reagents as mentioned. In the first step, the first reagent used is phenylmagnesium bromide in the solvent diethyl ether, and the second reagent is which represents the aqueous acidic condition. In the second step, the reagent is phosphoric acid and is the reaction temperature. Thus, the word form of the above synthetic scheme can be written as follows:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Conclusion

The given synthesis scheme is converted to word form by identifying the names of reactants, reagents, and products.

Interpretation Introduction

(b)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to products by reacting with the reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane, to produce phenylpropanone. Then, add the molecular bromine in the presence of acetic acid to form which further reacts with sodium acetate to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 19

The given synthetic route is of three steps. In the first step, the reactant having functional group ketone named phenylehtanone is converted to another ketone named phenylpropanone. In the second step, phenylpropanone is converted to alpha bromo ketone named , which, in the third step, is further converted to the final product having the ester functional group. In the first step, the first reagent used is lithium diisopropylamide, and the second reagent is iodomethane. In the second step, the reagent is molecular bromine in acetic acid. The reagent for the third step is sodium acetate. Thus, the word form of the above synthetic scheme can be written as follows:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane to produce phenylpropanone. Add the molecular bromine in presence of acetic acid to phenylpropanone to form which further reacts with sodium acetate to yield THE final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

Interpretation Introduction

(c)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants, and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Heat in aqueous hydrochloric acid to form , add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 29

The given synthetic route is of three steps. The nitro functional group remains as it is throughout the reaction sequence, and so, is not considered. In the first step, ether functional group is converted to an alcohol. In the second step, group of alcohol is replaced by bromine, which in the third step is replaced by . In the first step, the reagent used is that represents acidic condition where is the symbol used for heat. In the second step, the reagent is , phosphorous tribromide, and in the third step, the reagent used is sodium azide, . Thus, the word form of the above synthetic scheme can be written as follows:

Heat in aqueous hydrochloric acid to form , and add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

Answer 6

Chapter 13, Problem 13.28P

Interpretation Introduction

(a)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on the right side of the reaction arrow

() are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 7

In the given synthetic route, the reactant having functional group epoxide is converted to an alcohol named which is further converted to an alkene named on reaction with appropriate reagents as mentioned. In the first step, the first reagent used is phenylmagnesium bromide in the solvent diethyl ether, and the second reagent is which represents the aqueous acidic condition. In the second step, the reagent is phosphoric acid and is the reaction temperature. Thus, the word form of the above synthetic scheme can be written as follows:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Conclusion

The given synthesis scheme is converted to word form by identifying the names of reactants, reagents, and products.

Answer 7

Chapter 13, Problem 13.28P

Interpretation Introduction

(a)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on the right side of the reaction arrow

() are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Answer 8

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 7

In the given synthetic route, the reactant having functional group epoxide is converted to an alcohol named which is further converted to an alkene named on reaction with appropriate reagents as mentioned. In the first step, the first reagent used is phenylmagnesium bromide in the solvent diethyl ether, and the second reagent is which represents the aqueous acidic condition. In the second step, the reagent is phosphoric acid and is the reaction temperature. Thus, the word form of the above synthetic scheme can be written as follows:

The starting epoxide reacts with phenylmagnesium bromide in the solvent diethyl ether followed by aqueous acid, to form . Then, treat with phosphoric acid at to form .

Answer 13

Conclusion

The given synthesis scheme is converted to word form by identifying the names of reactants, reagents, and products.

Answer 14

Interpretation Introduction

(b)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to products by reacting with the reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane, to produce phenylpropanone. Then, add the molecular bromine in the presence of acetic acid to form which further reacts with sodium acetate to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 19

The given synthetic route is of three steps. In the first step, the reactant having functional group ketone named phenylehtanone is converted to another ketone named phenylpropanone. In the second step, phenylpropanone is converted to alpha bromo ketone named , which, in the third step, is further converted to the final product having the ester functional group. In the first step, the first reagent used is lithium diisopropylamide, and the second reagent is iodomethane. In the second step, the reagent is molecular bromine in acetic acid. The reagent for the third step is sodium acetate. Thus, the word form of the above synthetic scheme can be written as follows:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane to produce phenylpropanone. Add the molecular bromine in presence of acetic acid to phenylpropanone to form which further reacts with sodium acetate to yield THE final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

Answer 15

Interpretation Introduction

(b)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to products by reacting with the reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants and the functional groups produced in the product are to be identified.

Answer 16

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane, to produce phenylpropanone. Then, add the molecular bromine in the presence of acetic acid to form which further reacts with sodium acetate to yield the final product.

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Expert Solution

Answer 20

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 19

The given synthetic route is of three steps. In the first step, the reactant having functional group ketone named phenylehtanone is converted to another ketone named phenylpropanone. In the second step, phenylpropanone is converted to alpha bromo ketone named , which, in the third step, is further converted to the final product having the ester functional group. In the first step, the first reagent used is lithium diisopropylamide, and the second reagent is iodomethane. In the second step, the reagent is molecular bromine in acetic acid. The reagent for the third step is sodium acetate. Thus, the word form of the above synthetic scheme can be written as follows:

Phenylehtanone reacts with lithium diisopropylamide followed by iodomethane to produce phenylpropanone. Add the molecular bromine in presence of acetic acid to phenylpropanone to form which further reacts with sodium acetate to yield THE final product.

Answer 21

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

Answer 22

Interpretation Introduction

(c)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants, and the functional groups produced in the product are to be identified.

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Heat in aqueous hydrochloric acid to form , add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 29

The given synthetic route is of three steps. The nitro functional group remains as it is throughout the reaction sequence, and so, is not considered. In the first step, ether functional group is converted to an alcohol. In the second step, group of alcohol is replaced by bromine, which in the third step is replaced by . In the first step, the reagent used is that represents acidic condition where is the symbol used for heat. In the second step, the reagent is , phosphorous tribromide, and in the third step, the reagent used is sodium azide, . Thus, the word form of the above synthetic scheme can be written as follows:

Heat in aqueous hydrochloric acid to form , and add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

Answer 23

Interpretation Introduction

(c)

Interpretation:

The given synthesis scheme is to be converted to word form that can be used as instructions in the laboratory.

Concept introduction:

The synthesis scheme is the balanced chemical equation written for carrying out a sequence of reactions with specified steps. The synthetic step displays that the reactants are converted to the product by reacting with reagents in the required conditions.

The structures on the left side of the reaction arrow () are the reactants. The reagents used are written above the arrow, and the reaction conditions including solvent, temperature, pH, time of reaction, etc. are written below the arrow. If more than one sequence is combined in one step, then the reagents are numbered according to their sequence and can be written above and below the reaction arrow. In such cases, the reaction conditions are separated from the reactant or reagent by either a comma or a slash. The numbers given to reagents represent that the reaction goes to completion before the next reagent is added. The structures on right side of the reaction arrow () are the products. The product of the previous step is the reactant of the next step. While writing the synthetic scheme in word form, the functional groups involved in the reactants, and the functional groups produced in the product are to be identified.

Answer 24

Expert Solution

Answer to Problem 13.28P

The word form for the given synthesis scheme is:

Heat in aqueous hydrochloric acid to form , add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Expert Solution

Answer 28

Explanation of Solution

The given synthesis scheme is:

Organic Chemistry: Principles and Mechanisms (Second Edition), Chapter 13, Problem 13.28P , additional homework tip 29

The given synthetic route is of three steps. The nitro functional group remains as it is throughout the reaction sequence, and so, is not considered. In the first step, ether functional group is converted to an alcohol. In the second step, group of alcohol is replaced by bromine, which in the third step is replaced by . In the first step, the reagent used is that represents acidic condition where is the symbol used for heat. In the second step, the reagent is , phosphorous tribromide, and in the third step, the reagent used is sodium azide, . Thus, the word form of the above synthetic scheme can be written as follows:

Heat in aqueous hydrochloric acid to form , and add phosphorous tribromide to it to produce . Then, react with sodium azide to yield the final product.

Answer 29

Conclusion

The given synthesis scheme was converted to word form by identifying the names of reactants, reagents, and products.

Answer 30

Ch. 13 - Prob. 13.1P Ch. 13 - Prob. 13.2P Ch. 13 - Prob. 13.3P Ch. 13 - Prob. 13.4P Ch. 13 - Prob. 13.5P Ch. 13 - Prob. 13.6P Ch. 13 - Prob. 13.7P Ch. 13 - Prob. 13.8P Ch. 13 - Prob. 13.9P Ch. 13 - Prob. 13.10P

Answer to Problem 13.28P

Explanation of Solution

Answer to Problem 13.28P

Explanation of Solution

Answer to Problem 13.28P

Explanation of Solution

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