Essentials Of Materials Science And Engineering
Essentials Of Materials Science And Engineering
4th Edition
ISBN: 9781337670845
Author: ASKELAND
Publisher: Cengage
Question
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Chapter 13, Problem 13.26P
Interpretation Introduction

(a)

Interpretation:

The phases formed for the condition of oil (without agitation), when a bar of 1080 steel is quenched above eutectoid temperature should be determined.

Concept introduction:

Phase is defined as the homogeneous portion of the system having same physical and chemical characteristics.

Continuous cooling transformation (CCT) is used to determine the microstructure produced in the steel at various rates of cooling. In CTT diagram no region for bainite is observed. CTT curve for 1080 steel is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  1

TTT diagram is time temperature transformation diagram which shows the transformation occurring in the material at a given temperature as a function of time.

The TTT diagram for eutectoid steel is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  2

The graph shows the relationship at which the transformation occurs at a given temperature with respect to hardness of material with respect to time.

Expert Solution
Check Mark

Answer to Problem 13.26P

The required value of phase considering the condition of oil (without agitation) is fine pearlite.

Explanation of Solution

Given information:

Continuous cooling transformation curve for 1080 steel is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  3

Based on given information, using graph to determine the phase,

For the given condition of oil without agitation, the value of temperature considered is 18°C/s.

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  4

When the cooling of steel 1080 at the temperature of 18°C/s, the phase considered is fine pearlite.

The required value of phase considering the condition of oil (without agitation) is fine pearlite.

In order to obtain coarser pearlite, the required cooling rate should be less than 5°C/s. Therefore, coarse pearlite cannot be obtained by quenching but can be obtained using the annealing treatment of steel.

Interpretation Introduction

(b)

Interpretation:

The phases formed for the condition of oil (agitation), when a bar of 1080 steel is quenched above eutectoid temperature should be determined.

Concept introduction:

Phase is defined as the homogeneous portion of the system having same physical and chemical characteristics.

Continuous cooling transformation (CCT) is used to determine the microstructure produced in the steel at various rates of cooling. In CTT diagram no region for bainite is observed. CTT curve for 1080 steel is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  5

TTT diagram is time temperature transformation diagram which shows the transformation occurring in the material at a given temperature as a function of time.

The TTT diagram for eutectoid steel is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  6

The graph shows the relationship at which the transformation occurs at a given temperature with respect to hardness of material with respect to time.

Expert Solution
Check Mark

Answer to Problem 13.26P

The required value of phase considering the condition of oil (agitation) is pearlite with martensite.

Explanation of Solution

Based on given information, using graph to determine the phase,

For the given condition of oil without agitation, the value of temperature considered is 45°C/s.

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  7

When the cooling of steel 1080 at the temperature of 45°C/s, the phase considered is pearlite with martensite.

The required value of phase considering the condition of oil (agitation) is pearlite with martensite.

In order to obtain coarser pearlite, the required cooling rate should be less than 5°C/s. Therefore, coarse pearlite cannot be obtained by quenching but can be obtained using the annealing treatment of steel.

Interpretation Introduction

(c)

Interpretation:

The phases formed for the condition of oil (agitation), when a bar of 1080 steel is quenched above eutectoid temperature should be determined.

Concept introduction:

Phase is defined as the homogeneous portion of the system having same physical and chemical characteristics.

Continuous cooling transformation (CCT) is used to determine the microstructure produced in the steel at various rates of cooling. In CTT diagram no region for bainite is observed. CTT curve for 1080 steel is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  8

TTT diagram is time temperature transformation diagram which shows the transformation occurring in the material at a given temperature as a function of time.

The TTT diagram for eutectoid steel is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  9

The graph shows the relationship at which the transformation occurs at a given temperature with respect to hardness of material with respect to time.

Expert Solution
Check Mark

Answer to Problem 13.26P

The required value of phase considering the condition of water(agitation) is Martensite.

Explanation of Solution

Based on given information, using graph to determine the phase,

For the given condition of oil without agitation, the value of temperature considered is 190°C/s.

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  10

When the cooling of steel 1080 at the temperature of 190°C/s, the phase considered is Martensite.

The required value of phase considering the condition of water(agitation) is Martensite.

In order to obtain coarser pearlite, the required cooling rate should be less than 5°C/s. Therefore, coarse pearlite cannot be obtained by quenching but can be obtained using the annealing treatment of steel.

Interpretation Introduction

(d)

Interpretation:

The phases formed for the condition of Brine(no agitation), when a bar of 1080 steel is quenched above eutectoid temperature should be determined.

Concept introduction:

Phase is defined as the homogeneous portion of the system having same physical and chemical characteristics.

Continuous cooling transformation (CCT) is used to determine the microstructure produced in the steel at various rates of cooling. In CTT diagram no region for bainite is observed. CTT curve for 1080 steel is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  11

TTT diagram is time temperature transformation diagram which shows the transformation occurring in the material at a given temperature as a function of time.

The TTT diagram for eutectoid steel is shown below:

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  12

The graph shows the relationship at which the transformation occurs at a given temperature with respect to hardness of material with respect to time.

Expert Solution
Check Mark

Answer to Problem 13.26P

The required value of phase considering the condition of Brine(no agitation) is pearlite with martensite.

Explanation of Solution

Based on given information, using graph to determine the phase,

For the given condition of oil without agitation, the value of temperature considered is 90°C/s.

Essentials Of Materials Science And Engineering, Chapter 13, Problem 13.26P , additional homework tip  13

When the cooling of steel 1080 at the temperature of 90°C/s, the phase considered is Martensite with pearlite.

The required value of phase considering the condition of Brine(no agitation) is Martensite with pearlite.

In order to obtain coarser pearlite, the required cooling rate should be less than 5°C/s. Therefore, coarse pearlite cannot be obtained by quenching but can be obtained using the annealing treatment of steel.

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