1. Consider the following a unity feedback control system.R(s) +E(s)500(s+2)(s+5)(s+6)s(s+8)(s+10)(s+12)-Y(s)Find the followings:a) Type of the systemb) Static position error constant Kp, Static velocity error constant Ry and Staticacceleration error constant Kac) Find the steady-state error of the system for (i) step input 1(t), (ii) ramp input t 1(t),(iii) parabolic input t² 1(t).2. Repeat the above problem for the following system.R(s) + E(s)500(s + 2)(s + 5)(s+8)(s+ 10)(s+12)Y(s)3. Repeat the above problem for the following system.R(s) +E(s) 500(s+2)(s+4)(s+5)(s+6)(s+7)s²(s+8)(s+10)(s+12)Y(s)

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Answered: 1. Consider the following a unity…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

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Consider the feedback system below for which we intend to study both the stability and the steady-state properties. R(s) + 50 C(s) 2 s+1 a) Represent the system in a standard unity-feedback control structure and using any forms of your choice, construct a state-space representation of the closed-loop system. b) Using Routh-Hurtwitz criterion or any other means determine if the closed-loop system is stable or not. Specify the number of poles on the left-half s-plane, on the right-half s-plane and on the j w-axis.
6. Consider the feedback system shown in Figure 5. The process transfer function is marginally stable, The controller is the proportional-derivative (PD) controller G,(s) = K, +Kps. Determine if it is possible to find values of K, and K, such that the closed-loop system is stable. If so, obtain values of the controller parameters such that the steady-state tracking error E(s) = R(s)-Y(s) to a unit step input R(s) =1/s is e, = lim e(t) <0.1 and the damping of the closed-loop system is 5=V2/2. Controller Process E,(s) 4 R(s) Kp+Kps Y(s) +4 erwe Figure 5
QUESTION 1 A unity feedback system has open loop transfer function shown below. Find K1 so that the damping ratio = 0.4 and the peak time t,=2 seconds. Here the peak time tp = wa K1 s+ KzK2) HG(s) =
QUESTION4 Consider the feedback system in the figure with G(s) Using the Ziegler-Nichols Oscillation Method. %3D (s+1)(s+3)(s+10) for an ideal PID controller C(s) - K, ++ Kps determine the gains K K, and K. Choose the closest set of gains. C(s) G(s) OK, - 18, K, = 12.81, K, = 6.32 O Kp = 4.80, K, = 2.65, Kp = 2.18 O Kp - 47.52, K, = 85.57, K, - 12.60 %3D O K, - 68.64, K, = 143.27, Kp = 8.22
I need the answer as soon as possible
3. Can a series connection of two BIBO unstable systems ever be BIBO stable? What about a parallel connection and a negative feedback connection? Explain. Hint: Think pole-zero cancellation.
Why is the no encirclement about(-1+jo)?
. The block diagram of a unity feedback control system is shown below: R(s)- 20 (s+ 1) (s + 5) - C(s) Determine the time at which first undershoot occurs.
For a lead compensator whose zero is (-2,0) is used in a feedback control system to provide a phase lead of 45 .for desired pole location (S1=-2+3.3j), that represents the design specifications, this compensators pole is at
An uncompensated system shown in Figure 3(a) has forward transfer function G(s) with a unity feedback. a. Design a phase lead compensator shown in Figure 3(b) cascaded with the uncompensated system shown in Figure 3(a) that will have a 40% or better improvement of the settling time, at least 3 times improvement in percent overshoot. Assume a compensator zero at (given value zc = -10).Show all the complete solution.
A unity feedback system has a forward path transfer function G(s)=16/(s2+8s). Find the value of delat time , rise time, percentage overshoot, peak time and settling time.
The block diagram of a feedback control system is shown in the figure. The error signal is defined as e(t). (a) Find the steady-state errors in terms of K and K, when the input is a unit-ramp function. (b) Give the constraints on the values of K and K, so the answer is valid. Let n(t) = 0 for this part. (c) Find the steady-state value y(t) when n(t) is a unit-step function. Let r(t) =0. Assume that the system is stable. R(s) + E(s) 1+0.02s + N(s) + K S²(S+25) Ks+ Y(s)

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