Charge neutrality Since doped semiconductor remains electroneutral, the concentration of negative charges equals the concentration of positive charges. n+ Na,ionized p+Nd,ionized np = n; 2 2 N-Na N N d d р + 2 2 n = Nd-Na 2 + Na - 2 Na +n₁ 2 71/2 1/2 2 2 +n Concentration of electrons and holes 1. Calculate concentrations of electrons and holes at room temperature in Si and Ge with donor concentration of 1.5x10¹7 cm³ and acceptor concentration of 8x1016 cm-3. 2. Will these concentrations change much with the temperature increase to 100°C?
Charge neutrality Since doped semiconductor remains electroneutral, the concentration of negative charges equals the concentration of positive charges. n+ Na,ionized p+Nd,ionized np = n; 2 2 N-Na N N d d р + 2 2 n = Nd-Na 2 + Na - 2 Na +n₁ 2 71/2 1/2 2 2 +n Concentration of electrons and holes 1. Calculate concentrations of electrons and holes at room temperature in Si and Ge with donor concentration of 1.5x10¹7 cm³ and acceptor concentration of 8x1016 cm-3. 2. Will these concentrations change much with the temperature increase to 100°C?
Chapter59: Motor Startup And Troubleshooting Basics
Section: Chapter Questions
Problem 12SQ: How is a solid-state diode tested? Explain.
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Transcribed Image Text:Charge neutrality
Since doped semiconductor remains electroneutral, the concentration
of negative charges equals the concentration of positive charges.
n+ Na,ionized
p+Nd,ionized
np = n;
2
2
N-Na
N N
d
d
р
+
2
2
n =
Nd-Na
2
+
Na
-
2
Na
+n₁
2
71/2
1/2
2
2
+n
Concentration of electrons and holes
1. Calculate concentrations of electrons and holes at room temperature in Si
and Ge with donor concentration of 1.5x10¹7 cm³ and acceptor
concentration of 8x1016 cm-3.
2. Will these concentrations change much with the temperature increase to
100°C?
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