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1- Given the vectors M = -10ax +4ay - 8a; and N = 8ax +7ay - 2a, find: a) a unit vector in the direction of -M+2N. -M+2N=10ax - 4ay +8a2 +16ax +14ay - 4a₂ = (26,10,4) Thus a (26, 10, 4) |(26, 10, 4)| = (0.92, 0.36, 0.14) b) the magnitude of 5ax +N-3M: (5,0,0)+(8,7,-2)-(-30, 12,-24) = (43,-5, 22), and |(43, -5, 22)| = 48.6. c) |M||2N|(M+N): |(-10, 4, −8)||(16, 14, -4)|(-2, 11, -10) = (13.4)(21.6)(-2, 11, -10) = (-580.5, 3193,-2902)

1- Given the vectors M = -10ax +4ay - 8a; and N = 8ax +7ay - 2a, find: a) a unit vector in the direction of -M+2N. -M+2N=10ax - 4ay +8a2 +16ax +14ay - 4a₂ = (26,10,4) Thus a (26, 10, 4) |(26, 10, 4)| = (0.92, 0.36, 0.14) b) the magnitude of 5ax +N-3M: (5,0,0)+(8,7,-2)-(-30, 12,-24) = (43,-5, 22), and |(43, -5, 22)| = 48.6. c) |M||2N|(M+N): |(-10, 4, −8)||(16, 14, -4)|(-2, 11, -10) = (13.4)(21.6)(-2, 11, -10) = (-580.5, 3193,-2902)

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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1- Given the vectors M = -10ax +4ay - 8a; and N = 8ax +7ay - 2a, find: a) a unit vector in the direction of -M+2N. -M+2N=10ax - 4ay +8a2 +16ax +14ay - 4a₂ = (26,10,4) Thus a (26, 10, 4) |(26, 10, 4)| = (0.92, 0.36, 0.14) b) the magnitude of 5ax +N-3M: (5,0,0)+(8,7,-2)-(-30, 12,-24) = (43,-5, 22), and |(43, -5, 22)| = 48.6. c) |M||2N|(M+N): |(-10, 4, −8)||(16, 14, -4)|(-2, 11, -10) = (13.4)(21.6)(-2, 11, -10) = (-580.5, 3193,-2902)
Transcribed Image Text:1- Given the vectors M = -10ax +4ay - 8a; and N = 8ax +7ay - 2a, find: a) a unit vector in the direction of -M+2N. -M+2N=10ax - 4ay +8a2 +16ax +14ay - 4a₂ = (26,10,4) Thus a (26, 10, 4) |(26, 10, 4)| = (0.92, 0.36, 0.14) b) the magnitude of 5ax +N-3M: (5,0,0)+(8,7,-2)-(-30, 12,-24) = (43,-5, 22), and |(43, -5, 22)| = 48.6. c) |M||2N|(M+N): |(-10, 4, −8)||(16, 14, -4)|(-2, 11, -10) = (13.4)(21.6)(-2, 11, -10) = (-580.5, 3193,-2902)
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