Q2)a) consider the Circuit in figure 2 with initial conditions of Vc (o) = 5V, I₁ (o) = 1A, (i) redraw the circuit in the frequency domain using laplace Wansforms. (ii) using this circuit derive an equation for the Voltage across the inductor in the time domain.. 3.12 ww =V/3F ZH (figure 2) d) Solve the following second order differential equation using laplace transforms. d12 + 5 dx 3x=71 dt - with initial conditions x² (0) = 2, α(0) = 1
Q2)a) consider the Circuit in figure 2 with initial conditions of Vc (o) = 5V, I₁ (o) = 1A, (i) redraw the circuit in the frequency domain using laplace Wansforms. (ii) using this circuit derive an equation for the Voltage across the inductor in the time domain.. 3.12 ww =V/3F ZH (figure 2) d) Solve the following second order differential equation using laplace transforms. d12 + 5 dx 3x=71 dt - with initial conditions x² (0) = 2, α(0) = 1
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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
Transcribed Image Text:Q2)a) consider the Circuit in figure 2 with initial conditions of Vc (o) = 5V, I₁ (o) = 1A,
(i) redraw the circuit in the frequency domain using laplace Wansforms.
(ii)
using this circuit derive an
equation for the Voltage across the inductor in the time domain..
3.12
ww
=V/3F
ZH
(figure 2)
d) Solve the following second order differential equation using laplace transforms.
d12
+
5 dx 3x=71
dt
-
with initial conditions x² (0) = 2, α(0) = 1
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