Voc Vac w R1 23 where R₁ = 2.2KQ, R₂ = 4.7KQ, C=0.1uF, V = +5V, and V₂ = 3V peak f = 1KHz. • Use superposition to calculate the DC voltage at point X; V = 3.4V VDC=Vdc • Xc= R2 =5V R₁* R2 4.7ΚΩ 2.2ΚΩ* 4.7 ΚΩ -=3.405V Use superposition to calculate the AC (peak) voltage at point X; V = 2.05V_ 1 1 · = 15.992ΚΩ 2piFC 2П*1kHz*0.1uF 2.2ΚΩ 4.7ΚΩ RTH= 1.4ΚΩ 2.2k0+4.7kO Vx= 3 * 4.7 ΚΩ =2.05V 2.2ΚΩ+4.7ΚΩ Sketch what you think the scope will show at X:
Voc Vac w R1 23 where R₁ = 2.2KQ, R₂ = 4.7KQ, C=0.1uF, V = +5V, and V₂ = 3V peak f = 1KHz. • Use superposition to calculate the DC voltage at point X; V = 3.4V VDC=Vdc • Xc= R2 =5V R₁* R2 4.7ΚΩ 2.2ΚΩ* 4.7 ΚΩ -=3.405V Use superposition to calculate the AC (peak) voltage at point X; V = 2.05V_ 1 1 · = 15.992ΚΩ 2piFC 2П*1kHz*0.1uF 2.2ΚΩ 4.7ΚΩ RTH= 1.4ΚΩ 2.2k0+4.7kO Vx= 3 * 4.7 ΚΩ =2.05V 2.2ΚΩ+4.7ΚΩ Sketch what you think the scope will show at X:
Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter18: Resistive-inductive Parallel Circuits
Section: Chapter Questions
Problem 1PA: Incandescent lighting of 500 W is connected in parallel with an inductive load. A clamp-on ammeter...
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I need to figure out how to make an oscilliscope sketch from the VDC and VAC values.

Transcribed Image Text:Voc
Vac w
R1
23
where R₁ = 2.2KQ, R₂ = 4.7KQ, C=0.1uF, V = +5V, and V₂ = 3V peak f = 1KHz.
• Use superposition to calculate the DC voltage at point X; V = 3.4V
VDC=Vdc
•
Xc=
R2
=5V
R₁* R2
4.7ΚΩ
2.2ΚΩ* 4.7 ΚΩ
-=3.405V
Use superposition to calculate the AC (peak) voltage at point X; V = 2.05V_
1
1
· = 15.992ΚΩ
2piFC
2П*1kHz*0.1uF
2.2ΚΩ 4.7ΚΩ
RTH=
1.4ΚΩ
2.2k0+4.7kO
Vx= 3 *
4.7 ΚΩ
=2.05V
2.2ΚΩ+4.7ΚΩ
Sketch what you think the scope will show at X:
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