Consider the ROM table (AKA State Transition Table) below. If you created the associated programming table, what would the DATA entry be for the ADDRESS = BH? ROM TABLE: Present State Inputs Next State Decoder Output Select A3 A2 A1 A0 D4 D3 D2 D1 Do A B IN1 INO A B LWAX SDA SDB 0 0 0 0 00 1 0 0 0 0 0 1 00 1 0 0 0 0 1 X 0 0 1 0 0 0 1 X 0 10 1 0 1 0 1 0 1 0 1 1 0 0 0 1 1 1 1 1 1 0 0 1 0 0 0 10 0 1 0 1 0 0 1 1 0 1 1 0 1 0 1 0 1 1 0 1 0 1 0 1 1 11 1 1 0 1 1 X X 00 1 1 1 A 07 Hex B 04 Hex 1A Hex (මම ම D 1E Hex Consider the ROM table (AKA State Transition Table) below. If you created the associated programming table, what would the DATA entry be for the ADDRESS = 2H? ROM TABLE: Present Next Decoder State Inputs State Output Select A3 A2 A1 A0 D4 D3 D2 D1 Do A B IN1 INO ABLWAX SDA SDB 0 0 0 0 00 1 0 0 0 0 0 1 00 1 0 0 0 0 1 X 0 0 1 0 0 0 1 X 0 1 0 1 0 1 0 1 0 1 0 1 1 0 0 0 1 1 1 1 1 1 0 0 1 0 0 0 1 0 0 1 0 1 0 0 1 1 0 1 1 0 1 0 1 0 1 1 0 1 0 1 0 1 1 11 1 1 0 1 1 X 00 1 1 1 A 07 Hex (B) 04 Hex O O O 1A Hex 1E Hex
Consider the ROM table (AKA State Transition Table) below. If you created the associated programming table, what would the DATA entry be for the ADDRESS = BH? ROM TABLE: Present State Inputs Next State Decoder Output Select A3 A2 A1 A0 D4 D3 D2 D1 Do A B IN1 INO A B LWAX SDA SDB 0 0 0 0 00 1 0 0 0 0 0 1 00 1 0 0 0 0 1 X 0 0 1 0 0 0 1 X 0 10 1 0 1 0 1 0 1 0 1 1 0 0 0 1 1 1 1 1 1 0 0 1 0 0 0 10 0 1 0 1 0 0 1 1 0 1 1 0 1 0 1 0 1 1 0 1 0 1 0 1 1 11 1 1 0 1 1 X X 00 1 1 1 A 07 Hex B 04 Hex 1A Hex (මම ම D 1E Hex Consider the ROM table (AKA State Transition Table) below. If you created the associated programming table, what would the DATA entry be for the ADDRESS = 2H? ROM TABLE: Present Next Decoder State Inputs State Output Select A3 A2 A1 A0 D4 D3 D2 D1 Do A B IN1 INO ABLWAX SDA SDB 0 0 0 0 00 1 0 0 0 0 0 1 00 1 0 0 0 0 1 X 0 0 1 0 0 0 1 X 0 1 0 1 0 1 0 1 0 1 0 1 1 0 0 0 1 1 1 1 1 1 0 0 1 0 0 0 1 0 0 1 0 1 0 0 1 1 0 1 1 0 1 0 1 0 1 1 0 1 0 1 0 1 1 11 1 1 0 1 1 X 00 1 1 1 A 07 Hex (B) 04 Hex O O O 1A Hex 1E Hex
Chapter22: Sequence Control
Section: Chapter Questions
Problem 6SQ: Draw a symbol for a solid-state logic element AND.
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