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181, + j6(I1 – 12) + 4(I1 – 12) = 1020° -j1212 + 8(12 – l3) + 20490° + 4(I2 – 1) + j6(I2 –1) = 0 -j1013 + 1313 – 20290° + 8(13 – 12) = 0

181, + j6(I1 – 12) + 4(I1 – 12) = 1020° -j1212 + 8(12 – l3) + 20490° + 4(I2 – 1) + j6(I2 –1) = 0 -j1013 + 1313 – 20290° + 8(13 – 12) = 0

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Activity 1: You are testing an electrical device which can be modelled by the figure shown below: 18 -j12 a b j6 -j10 it E1 12 13 E2 13 The above electric circuit can be characterized by the following equations: 1811 + j6(11 – 12) + 4(11 – 12) = 1020° -j1212 + 8(12 – I3) + 20490° + 4(I2 – 4) + j6(I2 – I1) = 0 -j1013 + 1313 – 20290° + 8(13 – 12) = 0 Find I1, I2, and I3 using the Gaussian elimination method.
Transcribed Image Text:Activity 1: You are testing an electrical device which can be modelled by the figure shown below: 18 -j12 a b j6 -j10 it E1 12 13 E2 13 The above electric circuit can be characterized by the following equations: 1811 + j6(11 – 12) + 4(11 – 12) = 1020° -j1212 + 8(12 – I3) + 20490° + 4(I2 – 4) + j6(I2 – I1) = 0 -j1013 + 1313 – 20290° + 8(13 – 12) = 0 Find I1, I2, and I3 using the Gaussian elimination method.
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