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x = 1 * (10-(1,000)) (0.01 x10-6) = 1591.519.50 V = 5 (1000) 5,000 2.66157.85° V 1000+ 1 jwc -1000+ jan (0000)) (0.01 x106) V₁ = 5 (-) 1591.549) -1000+ (-j1591-5.49) 4.2331-32.141° V. 2. Is = 510° = 2.66157.85 mA 3. -1000+ (-) 1591-549). S = 1³ 2 2 = 1000+ (-; 1591-549) = 1000-) 1591.549 = 1899.6351-57.858 S = (2.66 × 10-3) ² (1879. ass = 0.01329 VA P=IR - P = (2.66 × 10-3) * (1000) = 7.0756 mW Q=1x = Q = (2.66x10-5)² (1591.549) = 0.01126 VAR 4. VR DATE: 57.85 32.151 c Vs = VM + Y₁ = 2.66 157.85 +4.233 1-32.141° = 4.99911539×663" √5 25 v

x = 1 * (10-(1,000)) (0.01 x10-6) = 1591.519.50 V = 5 (1000) 5,000 2.66157.85° V 1000+ 1 jwc -1000+ jan (0000)) (0.01 x106) V₁ = 5 (-) 1591.549) -1000+ (-j1591-5.49) 4.2331-32.141° V. 2. Is = 510° = 2.66157.85 mA 3. -1000+ (-) 1591-549). S = 1³ 2 2 = 1000+ (-; 1591-549) = 1000-) 1591.549 = 1899.6351-57.858 S = (2.66 × 10-3) ² (1879. ass = 0.01329 VA P=IR - P = (2.66 × 10-3) * (1000) = 7.0756 mW Q=1x = Q = (2.66x10-5)² (1591.549) = 0.01126 VAR 4. VR DATE: 57.85 32.151 c Vs = VM + Y₁ = 2.66 157.85 +4.233 1-32.141° = 4.99911539×663" √5 25 v

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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x = 1 * (10-(1,000)) (0.01 x10-6) = 1591.519.50 V = 5 (1000) 5,000 2.66157.85° V 1000+ 1 jwc -1000+ jan (0000)) (0.01 x106) V₁ = 5 (-) 1591.549) -1000+ (-j1591-5.49) 4.2331-32.141° V. 2. Is = 510° = 2.66157.85 mA 3. -1000+ (-) 1591-549). S = 1³ 2 2 = 1000+ (-; 1591-549) = 1000-) 1591.549 = 1899.6351-57.858 S = (2.66 × 10-3) ² (1879. ass = 0.01329 VA P=IR - P = (2.66 × 10-3) * (1000) = 7.0756 mW Q=1x = Q = (2.66x10-5)² (1591.549) = 0.01126 VAR 4. VR DATE: 57.85 32.151 c Vs = VM + Y₁ = 2.66 157.85 +4.233 1-32.141° = 4.99911539×663" √5 25 v
Transcribed Image Text:x = 1 * (10-(1,000)) (0.01 x10-6) = 1591.519.50 V = 5 (1000) 5,000 2.66157.85° V 1000+ 1 jwc -1000+ jan (0000)) (0.01 x106) V₁ = 5 (-) 1591.549) -1000+ (-j1591-5.49) 4.2331-32.141° V. 2. Is = 510° = 2.66157.85 mA 3. -1000+ (-) 1591-549). S = 1³ 2 2 = 1000+ (-; 1591-549) = 1000-) 1591.549 = 1899.6351-57.858 S = (2.66 × 10-3) ² (1879. ass = 0.01329 VA P=IR - P = (2.66 × 10-3) * (1000) = 7.0756 mW Q=1x = Q = (2.66x10-5)² (1591.549) = 0.01126 VAR 4. VR DATE: 57.85 32.151 c Vs = VM + Y₁ = 2.66 157.85 +4.233 1-32.141° = 4.99911539×663" √5 25 v
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