The vapor pressure in mmHg of a solution of 1.50 g of Br 2 in 145.0 g of CCl 4 at 300 K needs to be determined. Concept introduction: Colligative properties are the properties that depend on the number of particles present in the solution. Elevation in boiling point, depression in freezing point, lowering in vapor pressure and osmotic pressure are some common examples of colligative properties. Vapor pressure is the pressure at which is exerted by vapor on the liquid surface in a closed system when the system is in thermodynamic equilibrium. When a non-volatile solute is dissolved in a solvent to get the solution the vapor pressure decreases for the solution and it can be calculated with the help of Raoult’s law that states that the vapor pressure of the solution is the product of mole fraction of solvent and vapor pressure of the pure solvent.
The vapor pressure in mmHg of a solution of 1.50 g of Br 2 in 145.0 g of CCl 4 at 300 K needs to be determined. Concept introduction: Colligative properties are the properties that depend on the number of particles present in the solution. Elevation in boiling point, depression in freezing point, lowering in vapor pressure and osmotic pressure are some common examples of colligative properties. Vapor pressure is the pressure at which is exerted by vapor on the liquid surface in a closed system when the system is in thermodynamic equilibrium. When a non-volatile solute is dissolved in a solvent to get the solution the vapor pressure decreases for the solution and it can be calculated with the help of Raoult’s law that states that the vapor pressure of the solution is the product of mole fraction of solvent and vapor pressure of the pure solvent.
Solution Summary: The author explains that the vapor pressure in mmHg of a solution of 1.50 g Br 2 in 145.0-g CCl 4 at 300 K needs to be determined.
Science that deals with the amount of energy transferred from one equilibrium state to another equilibrium state.
Chapter 13, Problem 13.131SP
Interpretation Introduction
Interpretation:
The vapor pressure in mmHg of a solution of 1.50 g of Br2 in 145.0 g of CCl4 at 300 K needs to be determined.
Concept introduction:
Colligative properties are the properties that depend on the number of particles present in the solution. Elevation in boiling point, depression in freezing point, lowering in vapor pressure and osmotic pressure are some common examples of colligative properties. Vapor pressure is the pressure at which is exerted by vapor on the liquid surface in a closed system when the system is in thermodynamic equilibrium.
When a non-volatile solute is dissolved in a solvent to get the solution the vapor pressure decreases for the solution and it can be calculated with the help of Raoult’s law that states that the vapor pressure of the solution is the product of mole fraction of solvent and vapor pressure of the pure solvent.
Dr. Mendel asked his BIOL 260 class what their height was and what their
parent's heights were. He plotted that data in the graph below to determine if
height was a heritable trait.
A. Is height a heritable trait? If yes, what is the heritability value? (2 pts)
B. If the phenotypic variation is 30, what is the variation due to additive alleles?
(2 pts)
Offspring Height (Inches)
75
67.5
60
52.5
y = 0.9264x + 4.8519
55
60
65
MidParent Height (Inches)
70
75
12pt v
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Paragraph B IUA
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AT2 v
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Experiment:
Each team will be provided with 5g of a mixture of acetanilide and salicylic acid. You will divide it into three 1.5 g portions in separate 125 mL Erlenmeyer flasks savıng some for melting point analysis. Dissolve the mixture in each flask in ~60mL of DI water by heating to boiling on a hotplate. Take the flasks off the hotplate once you have a clear solution and let them stand on the bench top for 5 mins and then allow them to cool as described below.
Sample A-Let the first sample cool slowly to room temperature by letting it stand on your lab bench, with occasional stirring to promote crystallization.
Sample B-Cool the second sample 1n a tap-water bath to 10-15 °C
Sample C-Cool the third sample in an ice-bath to 0-2 °C
Results:
weight after recrystalization and melting point temp.
A=0.624g,102-115°
B=0.765g, 80-105°
C=1.135g, 77-108
What is the percent yield of A,B, and C.
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