Chapter 12.8, Problem 70SR

To determine

Calculate the amplitude and period of the function. Also draw the graph.

Answer to Problem 70SR

The amplitude and period is $3\&2\pi$ .

Explanation of Solution

Given: It is given in the question that the equation is $y=3\sin \theta$ .

Concept Used:

In this, use the concept of general equation of sine $y=a\sin b\theta$ where a is amplitude and $\frac{2\pi }{\left|b\right|}$ is the period.

Calculation: Here, the given equation is $y=3\sin \theta$

Now, $a=3$ so the amplitude is $3$ .

Since, b is $1$ so the period is $\frac{2\pi }{\left|b\right|}=\frac{2\pi }{\left|1\right|}=2\pi$

The graph of the function is:

  

Conclusion:

The amplitude and period is $3\&2\pi$ .