
To find: The side lengths of two different

Answer to Problem 46HP
a=20,b=23.6,c=8.4
a=10,b=11.8,c=4.2
Explanation of Solution
Given information:
A=550C=200
Given
A=550C=200
We know
Sum of Angles of a triangle is 1800
Using that
We get
A+B+C=1800⇒550+B+200=1800⇒750+B=1800⇒B=1800−750⇒B=1050
Using law of sines
We get
sinAa=sinBb⇒sin550a=sin1050b⇒b=asin1050sin550⇒b=a(0.966)0.82⇒b=1.18a
Again, using law of sines
We get
sinAa=sinCc⇒sin550a=sin200c⇒c=asin200sin550⇒c=a(0.342)0.82⇒c=0.42a
Therefore,
The side lengths will be in the ratio
a:b:c=a:1.18a:0.42a⇒a:b:c=1:1.18:0.42
Therefore,
If a=10
Then
b=1.18a⇒b=1.18a×10⇒b=11.8
c=0.42a⇒c=0.42a×10⇒c=4.2
One possible set is
a=10,b=11.8,c=4.2
If a=20
Then
b=1.18a⇒b=1.18a×20⇒b=23.6
c=0.42a⇒c=0.42a×20⇒c=8.4
Another set is
a=20,b=23.6,c=8.4
Chapter 12 Solutions
Glencoe Algebra 2 Student Edition C2014
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