
To find: Solve ΔABC .

Answer to Problem 34SGR
B=850C=490A=460
Explanation of Solution
Given information:
a=15b=21c=16
Given
a=15b=21c=16
The
We know
cosB=a2+c2−b22ac
On substituting values
We get
cosB=a2+c2−b22ac⇒cosB=152+162−2122(15)(16)⇒cosB=225+256−441480⇒cosB=481−441480⇒cosB=40480⇒cosB=0.083⇒B=cos−1(0.083)⇒B=850
Using law of sines
We get
sinBb=sinCc⇒sin85021=sinC16⇒sinC=16sin85021⇒sinC=16(0.9962)21⇒sinC=15.9421⇒sinC=0.76⇒C=sin−1(0.76)⇒C=490
Sum of angles of triangle is 1800
⇒A+B+C=1800⇒A+850+490=1800⇒1340+A=1800⇒A=1800−1340⇒A=460
Therefore,
B=850C=490A=460
Chapter 12 Solutions
Glencoe Algebra 2 Student Edition C2014
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