Chapter 12.6, Problem 9PPS

To determine

Calculate the lateral and surface area of cylinder having radius of $3\frac{2}{3}ft$ and height of $5\frac{1}{4}ft$

Answer to Problem 9PPS

Lateral area of cylinder= $120.929f{t}^2$

Surface area of cylinder= $205.37f{t}^2$

Explanation of Solution

Given:

Radius = $3\frac{2}{3}ft=3.666ft$

Height = $5\frac{1}{4}ft=5.25ft$

Calculations:

Here, we have to calculate lateral and surface area of cylinder.

We know that, surface area of cylinder is calculated as,

$Surfacearea=2\pi r^2+2\pi rh$

Where, $r$ is the radius of cylinder

h is the height of cylinder

Putting values in equation, we get

$\begin{array}{l}Surfacearea=2\pi r^2+2\pi rh\\ =(2\times \pi \times {3.666}^2)+(2\times \pi \times 3.666\times 5.25)\\ =84.443+120.929\\ =205.37f{t}^2\end{array}$

We know that, lateral surface area of cylinder is calculated as,

$\begin{array}{l}Surfacearea=2\pi rh\\ =(2\times \pi \times 3.666\times 5.25)\\ =120.929f{t}^2\end{array}$

Conclusion:

Therefore, we are able to calculate lateral and surface area of cylinder.