Chapter 12.4, Problem 2AGP

To determine

The volume of the cone whose radius and height is $6ft,20ft$ respectively.

Answer to Problem 2AGP

The volume of the cone is $753.98i{n}^3$

Explanation of Solution

Given:

  $\begin{array}{l}r=6ft\\ h=20ft\end{array}$

Concept Used:

The volume of the cone is given by the following expression:

  $V=\pi r^2\frac{h}{3}$

Where,

Radius of cone: $r$

Height of cone: $h$

Calculation:

The volume of the cone is given by the following expression:

  $V=\pi r^2\frac{h}{3}$

Put the given data in eq.

  $\begin{array}{l}V=\pi r^2\frac{h}{3}\\ V=\pi r^2\frac{h}{3}\\ V=\pi {\left(6\right)}^2\frac{20}{3}\\ V=753.98i{n}^3\end{array}$

Conclusion:

Hence, the volume of the figure is $753.98i{n}^3$