Chapter 12.5, Problem 6PPS

To determine

The lateral and surface area of the prism.

  

Answer to Problem 6PPS

The lateral is $L=144f{t}^2$

The surface of area is $S=216f{t}^2$

Explanation of Solution

Given:

  

Concept Used:

Lateral :

  $2\left(length+breadth\right)\times height$

Surface Area:

  $2\times length\times breadth\times height$

Calculation:

  

  $L=Ph$

  $\begin{array}{l}=2\left(6+6\right)\left(6\right)\\ =2\left(12\right)\left(6\right)\\ =144f{t}^2\end{array}$

Surface of Area:

  $S=Ph+2B$

  $\begin{array}{l}=144+2\left(6\right)\left(6\right)\\ =144+72\\ =216f{t}^2\end{array}$

Conclusion:

Hence, the lateral is $L=144f{t}^2$

The surface of area is $S=216f{t}^2$