Chapter 12.4, Problem 33STP

To determine

To find: Volume of a cone.

Answer to Problem 33STP

Volume of the cone $=696.217f{t}^3$so option (h) is correct.

Explanation of Solution

Given:

  $8335.07f{t}^3$

  $696.26f{t}^3$

  $2785.02f{t}^3$

  $618.89f{t}^3$

Concept used:

Volume of cone is calculated as,

  $V=\pi r^3\frac{h}{3}$

Where,

  $V=$ volume of cone

  $r=$ radius of cone

  $H=$ height of cone.

Diameter of the cone $=13.5f$

Radius of the cone $r=\frac{d}{2}=\frac{13.5}{2}=6.75ft$

Volume of cone is calculated as,

  $V=\pi r^2\frac{h}{3}$

Now put the values in the equation,

  $V=\pi r^2\frac{h}{3}$

  $V=\pi {\left(6.75\right)}^2\frac{14.6}{3}$

  $\begin{array}{l}V=\pi \left(45.56\right)\left(4.86\right)\\ V=696.217f{t}^3\end{array}$

Volume of the cone $=696.217f{t}^3$

Conclusion:

Thus, Volume of the cone $=696.217f{t}^3$so option (h) is correct.