Chapter 12.6, Problem 1CYU

To determine

The surface area and lateral surface area of the cylinder:

  

Answer to Problem 1CYU

The surface area and lateral surface area of the given cylinder is $2059m{m}^2$ and $1492.25m{m}^2$ respectively.

Explanation of Solution

Given:

  

  $\begin{array}{l}d=19mm\\ h=25mm\end{array}$

Concept Used:

The surface area of cylinderis given by the following expression:

  $A=2\pi rh+2\pi r^2$

The lateral surface area of cylinder is given by the following expression:

  $LSA=2\pi rh$

Where,

Radius of cylinder: $r$

Height of cylinder: $h$

Calculation:

The surface area of cylinder:

  $A=2\pi rh+2\pi r^2$

Put the given data:

  $\begin{array}{l}A=2\pi rh+2\pi r^2\\ A=\left(2\pi \times \frac{19}{2}\times 25\right)+2\pi {\left(\frac{19}{2}\right)}^2\\ A=1492.25+567.06\\ A=2059m{m}^2\end{array}$

The lateral surface area of cylinder:

  $LSA=2\pi rh$

Put the given data:

  $\begin{array}{l}LSA=2\pi rh\\ LSA=2\pi \times \frac{19}{2}\times 25\\ LSA=1492.25m{m}^2\end{array}$

Conclusion:

Hence,

The surface area of cylinder is $A=2059m{m}^2$

The lateral surface area of cylinder is $LSA=1492.25m{m}^2$