Chapter 12.4, Problem 8PPE

To determine

To find: The minimum, first quartile, median, third quartile, and maximum of given data set.

Answer to Problem 8PPE

  $\begin{array}{l}\text{Minimum}=5\\ \text{Maximum}=12\\ \text{Median}\left(Q_2\right)=10\\ \text{First quartile}\left(Q_1\right)=7\\ \text{Third quartile}\left(Q_3\right)=11\end{array}$

Explanation of Solution

Given information:

A data set is given as − $12\text{ 10 11 7 8 10 5}$ .

Calculation:

Given data set is $12\text{ 10 11 7 8 10 5}$ .

Arranging the data set from least to greatest −

  $5\text{ 7 8 10 10 11 12}$

  $\begin{array}{l}\text{Minimum}=5\\ \text{Maximum}=12\\ \text{Median}\left(Q_2\right)=10\\ \text{First quartile}\left(Q_1\right)=7\\ \text{Third quartile}\left(Q_3\right)=11\end{array}$