Chapter 12.4, Problem 10PPE

To determine

To find: The minimum, first quartile, median, third quartile, and maximum of given data set.

Answer to Problem 10PPE

  $\begin{array}{l}\text{Minimum}=49\\ \text{Maximum}=67\\ \text{Median}\left(Q_2\right)=52\\ \text{First quartile}\left(Q_1\right)=50.5\\ \text{Third quartile}\left(Q_3\right)=54\end{array}$

Explanation of Solution

Given information:

A data set is given as − $\text{55 53 67 52 50 49 51 52 52}$ .

Calculation:

Given data set is $\text{55 53 67 52 50 49 51 52 52}$ .

Arranging the data set from least to greatest −

  $\text{49 50 51 52 52 52 53 55 67}$

  $\begin{array}{l}\text{Minimum}=49\\ \text{Maximum}=67\\ \text{Median}\left(Q_2\right)=52\\ \text{First quartile}\left(Q_1\right)=\frac{50+51}{2}=50.5\\ \text{Third quartile}\left(Q_3\right)=\frac{53+55}{2}=54\end{array}$