Chapter 12.1, Problem 16PPE

To determine

To find: the multiplication of the given matrix.

Answer to Problem 16PPE

  $0\left[\begin{array}{l}5.3-7.2\\ -1.80.6\end{array}\right]=0$ .

Explanation of Solution

Given:

The given matrix is $0\left[\begin{array}{l}5.3-7.2\\ -1.80.6\end{array}\right]$ .

Concept used:

Scalar multiplication of the matrix: scalar multiplication refers to the product of a real number and a matrix. In scalar multiplication, each element in the matrix is multiplied by the given scalar. 

Calculation:

The given matrix is $0\left[\begin{array}{l}5.3-7.2\\ -1.80.6\end{array}\right]$ .

Since, each element in the matrix is multiplied by the given scalar.

Therefore, multiply the matrix. Now,

  $\begin{array}{l}0\left[\begin{array}{l}5.3-7.2\\ -1.80.6\end{array}\right]=\left[\begin{array}{l}0\times 5.30\times \left(-7.2\right)\\ 0\times \left(-1.8\right)0\times 0.6\end{array}\right]\\ =\left[\begin{array}{l}00\\ 00\end{array}\right]=0\end{array}$

Hence, the multiplication of the given matrix is $0\left[\begin{array}{l}5.3-7.2\\ -1.80.6\end{array}\right]=0$ .