Chapter 12.4, Problem 1P

a.

To determine

To find: The minimum, first quartile, median, third quartile, and maximum of given data set.

Answer to Problem 1P

  $\begin{array}{l}\text{Minimum}=100\\ \text{Maximum}=105\\ \text{Median}\left(Q_2\right)=101\\ \text{First quartile}\left(Q_1\right)=100\\ \text{Third quartile}\left(Q_3\right)=104\end{array}$

Explanation of Solution

Given information:

A data set is given as − $\text{95 85 75 85 65 60 100 105 75 85 75}$ .

Calculation:

Given data set is $\text{95 85 75 85 65 60 100 105 75 85 75}$ .

Arranging the data set from least to greatest −

  $\text{60 65 75 75 75 85 85 85 95 100 105}$

  $\begin{array}{l}\text{Minimum}=60\\ \text{Maximum}=105\\ \text{Median}\left(Q_2\right)=85\\ \text{First quartile}\left(Q_1\right)=75\\ \text{Third quartile}\left(Q_3\right)=95\end{array}$

b.

To determine

To find: The minimum, first quartile, median, third quartile, and maximum of given data set.

Answer to Problem 1P

  $\begin{array}{l}\text{Minimum}=5\\ \text{Maximum}=53\\ \text{Median}\left(Q_2\right)=15\\ \text{First quartile}\left(Q_1\right)=7\\ \text{Third quartile}\left(Q_3\right)=21\end{array}$

Explanation of Solution

Given information:

A data set is given as − $\text{11 19 7 5 21 53}$ .

Calculation:

Given data set is $\text{11 19 7 5 21 53}$ .

Arranging the data set from least to greatest −

  $\text{5 7 11 19 21 53}$

  $\begin{array}{l}\text{Minimum}=5\\ \text{Maximum}=53\\ \text{Median}\left(Q_2\right)=\frac{11+19}{2}=15\\ \text{First quartile}\left(Q_1\right)=7\\ \text{Third quartile}\left(Q_3\right)=21\end{array}$