
Brock Biology of Microorganisms (14th Edition)
14th Edition
ISBN: 9780321897398
Author: Michael T. Madigan, John M. Martinko, Kelly S. Bender, Daniel H. Buckley, David A. Stahl, Thomas Brock
Publisher: PEARSON
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Chapter 12.4, Problem 2MQ
Summary Introduction
Earlier, the biologist are classified the living organisms by into five kingdoms: animals, plants, bacteria,
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Chapter 12 Solutions
Brock Biology of Microorganisms (14th Edition)
Ch. 12.1 - What characteristics would have made the surface...Ch. 12.1 - How do we know when oceans were first present on...Ch. 12.1 - What lines of reasoning support the hypothesis...Ch. 12.2 - Why is the origin of cyanobacteria considered a...Ch. 12.2 - What caused the development of banded iron...Ch. 12.2 - What lines of evidence indicate that microbial...Ch. 12.3 - What evidence supports the idea that the...Ch. 12.3 - Prob. 2MQCh. 12.3 - In what ways are modern eukaryotes a combination...Ch. 12.4 - Prob. 1MQ
Ch. 12.4 - Prob. 2MQCh. 12.4 - Prob. 3MQCh. 12.5 - How are DNA sequences obtained for phylogenetic...Ch. 12.5 - What does a phylogenetic tree depict?Ch. 12.5 - Prob. 3MQCh. 12.6 - What are the different processes that give rise to...Ch. 12.6 - What is the difference between selection and...Ch. 12.6 - In the experiment of Figure 13.12, why did the...Ch. 12.7 - What is the difference between the core and pan...Ch. 12.7 - What kind of recombination might have the greatest...Ch. 12.7 - What effects do deletions have on the evolution of...Ch. 12.8 - What is the difference between taxonomy and...Ch. 12.8 - What are some key criteria from the phylogenetic...Ch. 12.8 - How many species of Bacteria and Archaea have been...Ch. 12.9 - What class of genes is used in MLST analyses?Ch. 12.9 - How is ribotyping different from rep-PCR?Ch. 12.9 - What is FAME analysis?Ch. 12.10 - What roles do culture collections play in...Ch. 12.10 - What is the IJSEM and what taxonomic function does...Ch. 12.10 - Why might viable cell cultures be of more use in...Ch. 12 - Prob. 1RQCh. 12 - Prob. 2RQCh. 12 - Prob. 3RQCh. 12 - What is the endosymbiotic hypothesis for the...Ch. 12 - Prob. 5RQCh. 12 - REVIEW QUESTIONS
6. What major physiological and...Ch. 12 - Prob. 7RQCh. 12 - Prob. 8RQCh. 12 - Prob. 9RQCh. 12 - What is the difference between a gene tree and an...Ch. 12 - Prob. 11RQCh. 12 - Prob. 12RQCh. 12 - What is fitness? To what degree does fitness...Ch. 12 - What are some processes that influence the content...Ch. 12 - Prob. 15RQCh. 12 - What is the "species problem" and why is the...Ch. 12 - Prob. 17RQCh. 12 - Prob. 18RQCh. 12 - Prob. 19RQCh. 12 - Prob. 20RQCh. 12 - Prob. 21RQCh. 12 - Compare and contrast the physical and chemical...Ch. 12 - For the following sequences, construct the...Ch. 12 - Imagine that you have been given several bacterial...Ch. 12 - Imagine that you have discovered a new form of...
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- Design a grafting experiment to determine if limb mesoderm determines forelimb / hindlimb identity. Include the experiment, a control, and an interpretation in your answer.arrow_forwardThe Snapdragon is a popular garden flower that comes in a variety of colours, including red, yellow, and orange. The genotypes and associated phenotypes for some of these flowers are as follows: aabb: yellow AABB, AABb, AaBb, and AaBB: red AAbb and Aabb: orange aaBB: yellow aaBb: ? Based on this information, what would the phenotype of a Snapdragon with the genotype aaBb be and why? Question 21 options: orange because A is epistatic to B yellow because A is epistatic to B red because B is epistatic to A orange because B is epistatic to A red because A is epistatic to B yellow because B is epistatic to Aarrow_forwardA sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forward
- A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forward
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- Explain what age of culture is most likely to produce an endospore?arrow_forwardExplain why hot temperatures greater than 45 degrees celsius would not initiate the sporulation process in endospores?arrow_forwardEndospore stain: Consider tube 2 of the 7-day bacillus culture. After is was heated, it was incubated for 24 hours then refrigerated. Do you think the cloudiness in this tube is due mostly to vegetative cells or to endospores? Explain your reasoningarrow_forward
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